An ideal gas with 2.20 mol is initially in state 1 with pressure p, = 17.0 atm and volume V, = 1060 cm3. First it is taken to state 2 with pressure p2 = 1.70p1 and volume V2 = 1.80V1. Then it is taken to state 3 with pressure p3 = 2.10p, and volume V3 = 0.476V1. What is the temperature of the gas in (a) state 1 and (b) state 2? (c) What is the net change in internal energy from state 1 to state 3?

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An ideal gas with 2.20 mol is initially in state 1 with pressure p1 = 17.0 atm and volume V = 1060 cm. First it is taken to state 2 with
pressure p2 = 1.70p, and volume V2 = 1.80V1. Then it is taken to state 3 with pressure p3 = 2.10p, and volume V3 = 0.476V1. What is
the temperature of the gas in (a) state 1 and (b) state 2? (c) What is the net change in internal energy from state 1 to state 3?
3
%3D
%3D
%3D
%3D
(a) Number
Units
(b) Number
Units
Units
(c) Number
Transcribed Image Text:An ideal gas with 2.20 mol is initially in state 1 with pressure p1 = 17.0 atm and volume V = 1060 cm. First it is taken to state 2 with pressure p2 = 1.70p, and volume V2 = 1.80V1. Then it is taken to state 3 with pressure p3 = 2.10p, and volume V3 = 0.476V1. What is the temperature of the gas in (a) state 1 and (b) state 2? (c) What is the net change in internal energy from state 1 to state 3? 3 %3D %3D %3D %3D (a) Number Units (b) Number Units Units (c) Number
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