An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 500 mm. The cross-sectional dimensions of the beam are b₁ = 33 mm, d₁ = 109 mm, b₂ = 20 mm, d₂ = 20 mm, and a = 6.5 mm. For this material, the allowable tensile bending stress is 16 MPa, and the allowable compressive bending stress is 11 MPa. Determine the largest moment M that can be applied as shown to the beam.

An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 500 mm. The cross-sectional dimensions of the beam are b₁ = 33 mm, d₁ = 109 mm, b₂ = 20 mm, d₂ = 20 mm, and a = 6.5 mm. For this material, the allowable tensile bending stress is 16 MPa, and the allowable compressive bending stress is 11 MPa. Determine the largest moment M that can be applied as shown to the beam.

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter6: Introduction To Mechanical Properties

Section: Chapter Questions

Problem 6.3P: Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2...

See similar textbooks

Related questions

Q: polymer a bending moment M. zth of the eam Is L dimensions of the beam are b, = 33 mm, di = 102 mm,…

A: It is asked to calculate maximum moment (M) that can be applied.

Q: Problem 11. [Concepts: Calculating stress from internal forces, nonlinear stress-strain response,…

A: a) Determine the yield strength assuming a 0.2% offset.b) If a bar of this material has a length of…

Q: 1.17 Figure P1.17 shows the stress-strain relations of metals A and B during tension tests until…

A: Any pressure of a solid object creates a stretched internal stress, similar to the spring-turning…

Q: Determine the following: a. Young's modulus within the linear portion b. Tangent modulus at a stress…

A: a).Young's Modulus : At the proportional limit, stress is directly proportional to strain stress α…

Q: An extruded polymer beam is subjected to a bending moment M. The length of the bear is L = 500 mm.…

A: Given data Allowable tensile bendig stress = 18 MPa Allowable compressive bending stress = 9 MPa

Q: Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion…

A: It is that point on stress-strain curve, till which stress is linearly varying with strain. As per…

Q: Data taken from a stress-strain test for a brittle alloy are given in the table. The curve is linear…

A: , ksi, in/in0034.30.000843.50.001347.00.001749.00.002149.50.0023The rupture stress,

Q: The strain gauge measurement of a steel plate indicate the principle strains are 0.003 and 0.001.…

A: Principle strains- ε1=0.003ε2=0.001E=200 GPaμ=0.33

Q: A steel alloy specimen having a rectangular cross section of dimensions 19.1 mm x 3.1 mm (0.7520 in.…

Q: A steel plate is bent into a circular arc of radius 10 m. If the plate section be 120 mm wide and 20…

A: Given: E=2×105 Nmm2. Arc radius, R = 10 m. Area, A=120 mm×20 mm. y = 10 mm.

Q: An aluminum alloy rod has a circular cross section with a diameter of 8mm. The rod is subjected to a…

Q: An aluminum alloy rod has a circular cross section with a diameter of 7mm. The rod s subjected to a…

Q: If Poisson's ratio is 0.42, the Modulus of rigidity is 70.4225 GPa, and the bulk modulus is 416.66…

Concept explainers

Material Properties

Construction in civil engineering demands high strength, durability, and longevity. These targets can be achieved by better design and analysis, along with the correct choice of materials. Different materials have different properties and hence, they respond and performs differently under the various condition of external loadings. It is therefore a critical task of an engineer to select the right material based on the property that the material is supposed to function in real-time. When speaking about the property, there are different categories of material properties like chemical property, physical property, mechanical property, electrical property, magnetic property, thermal property, etc. These material properties form the basis of material selection in various applications.

Question

An extruded polymer beam is subjected to a
bending moment M. The length of the beam is
L = 500 mm. The cross-sectional dimensions of
the beam are b₁ = 33 mm, d₁ = 109 mm, b₂ = 20
mm, d₂ = 20 mm, and a = 6.5 mm. For this
material, the allowable tensile bending stress is
16 MPa, and the allowable compressive
bending stress is 11 MPa. Determine the
largest moment M that can be applied as shown
to the beam.
b₂
a
M
B
A
Answer:
M =
L
d₂
N•m
b₁
d₁

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step by step

Solved in 5 steps with 8 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.
A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?
A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.
Estimate the elastic and plastic strain at the ultimate tensile strength in the low-carbon steel specimen in Figure 6.16.
For silver at a tensile stress of 7 MPa and a temperature of 839C , there are two equally contributing creep mechanisms. What are they?