An experiment was performed in order to determine the concentration of a persulfate ( S2O8^-2) solution 2 I^- (aq) + S2O8^2- (aq) —> I2 (aq) + 2 SO4^2- (aq) A 25.00 mL aliquot of .1500 M KI solution was titrated to a purple blue endpoint with soduim persulfate as the titrant. The intial buret reading was 1.25 mL and the final buret reading was 15.78 mL. Calculate the concentration of the soduim persulfate. Determine the oxidation number of iodine, sulfur, and oxygen in the reaction above and determine which species is oxidized and which is reduced.
An experiment was performed in order to determine the concentration of a persulfate ( S2O8^-2) solution 2 I^- (aq) + S2O8^2- (aq) —> I2 (aq) + 2 SO4^2- (aq) A 25.00 mL aliquot of .1500 M KI solution was titrated to a purple blue endpoint with soduim persulfate as the titrant. The intial buret reading was 1.25 mL and the final buret reading was 15.78 mL. Calculate the concentration of the soduim persulfate. Determine the oxidation number of iodine, sulfur, and oxygen in the reaction above and determine which species is oxidized and which is reduced.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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An experiment was performed in order to determine the concentration of a persulfate ( S2O8^-2) solution
2 I^- (aq) + S2O8^2- (aq) —> I2 (aq) + 2 SO4^2- (aq)
A 25.00 mL aliquot of .1500 M KI solution was titrated to a purple blue endpoint with soduim persulfate as the titrant. The intial buret reading was 1.25 mL and the final buret reading was 15.78 mL. Calculate the concentration of the soduim persulfate.
Determine the oxidation number of iodine, sulfur, and oxygen in the reaction above and determine which species is oxidized and which is reduced.
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Can you please explain step 3? Do I just solve for M in that equation to obtain the M amount? Can I multiply the 0.1500M with the single M on the other side of the =.
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