An experiment was conducted to compare anxiety levels among children induced between looking at snakes and pictures of snakes. The following data were collected from a sample of 10 children with orphidiophobia (fear of snakes). Use a =1.01. PARTICIPANT 1 Anxiety 2 3 30 4 30 5 7 8 10 20 25 25 35 50 55 40 25 score (real snakes) Anxiety 15 20 35 35 20 32 48 50 40 35 score (pictures)
Q: below miarzes data from a survey o sample of women. Osing 01 significance level, and assuming that…
A: We want to find the test statistic
Q: A poll was conducted to investigate opinions about global warming. The respondents who answered yes…
A:
Q: Researchers in a statistics course at a Texas college wanted to investigate the optimism in…
A: Given that, The objective of the research study was to investigate the optimism in receiving a job…
Q: Past studies have indicated that the percentage of smokers is estimated to be about 33%. Given the…
A:
Q: The table below summarizes data from a survey of a sample of women. Using a 0.05 significance…
A: The given table is as follows:
Q: Source DF Age Error Total 2 45 47 SS MS 137.78 68.89 6899.54 153.32 7037.32 F 0.45 side ed H) State…
A: If p value is greater than alpha we fail to reject null hypothesis otherwise we reject it
Q: We predict that children exhibit more aggressive act after watching a violent television show. The…
A: Given, The scores for ten children were recorded before they watched a violent show and then after…
Q: Lacey is interested in determining whether people who have experienced a traumatic event experience…
A: Given : Lacey is interested in determining whether people who have experienced a traumatic event…
Q: You want to test whether the proportion of men who smoke is…
A: Given that Male Female Sample size (n1) = 200 Sample size (n2) = 200 Smoke (x1) = 62 Smoke…
Q: People with z-scores greater than 2.5 on an IQ test are considred as geniuses. If IQ tests have a…
A: given data, μ=100σ=16z- scores greater than 2.5 on an IQ test are considred as geniuses.cutoff…
Q: The following are body mass index (BMI) scores measured in 9 patients who are free of diabetes and…
A: Mean:The formula for finding mean is shown below:x
Q: In an experiment to compare anxiety levels induced between looking at real spiders and pictures of…
A:
Q: A food company is developing a low-calorie granola bar, and the company is interested in whether the…
A: There were 100 male and 100 female volunteers available for purposes of evaluation. Both males and…
Q: In a research study, 100 college students took a personal finances class and 100 students took a…
A: Given, For finance class student, Sample mean=x¯ = 29.7 Sample sd =s1 =7.8 Sample size =n1= 100…
Q: Maria and Clara did questionnaires for samples of undergraduate students. Amongst other things, the…
A: Given: The results from questionnaire are given. The higher scores show greater approval of…
Q: Do sports drinks help prevent cramps in endurance sports? At the end of a marathon, officials will…
A: Observational study: In observational study, the individuals of the study are observed by the…
Q: 1) Find the standardized t test 2) Find the P-values 3) Decide whether to reject or fail to reject…
A: For In-Home Treatment Standard Deviation, s: 2.2070 Count, N: 20 Sum, Σx: 83 Mean, x̄: 4.15…
Q: 3. A researcher was interested in the effects of a drug on depression. Subjects were randomly…
A:
Q: A researcher wants to investigate whether mood is related to chocolate consumption. She recruits a…
A: Claim : The mood is related to chocolate consumption we have to use Chi-square test of independence…
Q: We predict that children exhibit more aggressive act after watching a violent television show. The…
A: Given : We have given that , Sample 1 (after TV show): 5,6,4,4,7,3,2,1,4,1 Sample 2 (before TV…
Q: A locally owned coffee shop claims that the mean waiting time for its costumers to be served is the…
A:
Q: Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation…
A: a:For the given data, the chi-square test for association is appropriate.Null Hypothesis:H0: The…
Q: The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level,…
A: As per our guidelines, we are allowed to answer first three sub-parts only. Thanks The following…
Q: The table below summarizes data from a survey of a sample of women. Using a 0.05 significance…
A: Chi square test of indepence.
Q: This was a question on my homework and I would like to know if I answered it correctly. Thank you…
A: Odds (O):The “odds” of the occurrence of an event is the ratio of the number of occurrences of the…
Q: The owner of Maumee Ford-Mercury-Volvo wants to study the relationship between the age of a car and…
A: CarAge (Years)Selling Price…
Q: Explain why different conclusions were reached in the hypothesis tests of parts (a) and (b). Getting…
A: Given,the two hypothesis tests for proportion test.The sample sizes were 600 in one test and 100 in…
Q: A researcher conducts an independent-measures study examining how the brain chemical serotonin is…
A: A. Null and alternate hypotheses: The investigator is specifically interested to test whether the…
Q: We predict that children exhibit more aggressive act after watching a violent television show. The…
A: Discrete quantitative data: The discrete quantitative data takes the values that are pure numbers…
Q: A social psychologist recently developed a childhood-memories test that is intended to measure how…
A:
Q: A research team is interested in determining if there is a relationship between death anxiety and…
A: Here we want to test if there is any relation between death anxiety and religiosity.
Q: Which of the following significance levels gives you the greatest chance of finding a significant…
A: The level of significance is the probability of rejecting the null hypothesis when it is true.
Q: The table below summarizes data from a survey of a sample of women. Using a 0.05 significance…
A: Chi-square test goodness of fit
Q: The following data are from a study on Botox injections. Patients received a high-dose injection in…
A: To conduct a test to compare the percentages of individuals who have less pain in the E eye vs. the…
Q: The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level,…
A: Steps to find the test statistic. The calculations have been done in EXCEL. Denote oij as the…
Q: John is interested in whether there is a relationship between gender and attitudes towards flogging…
A: Solution: Note: Hello! As you have posted more than 3 sub parts, we are answering the first 3…
Q: A clinical psychologist is investigating the relationship between sleep and feelings of anxiety. For…
A: The sum of squares of in "Hours of sleep" is SSx=16 The sum of squares of in "Anxiety scores" is…
Q: The researchers reported: Consumer masculinity was strongly correlated with appearance-related…
A: Given that, Self-esteem =(r = 0.40, p < .001) Media influence= (r = 0.62, p < .001) overall…
Q: Which of the following scenario is an example of a pretest–posttest design? Group of answer choices…
A: Pretest posttest design: It is an experiment where measurements are taken before and after a…
Q: Social functioning is the ability for an individual to interact or adapt in a normal or usual way in…
A: 1.The hypotheses for the provided test can be written as:
Q: The table below summarizes data from a survey of a sample of women. Using a 0.01 significance…
A: Here it is needed to test, whether the proportions of agree/disagree responses are the same for…
Q: A study of the effect of television commercials on 12-year-old children measured their attention…
A: Given: A study of the effect of television commercials on 12-year-old children measured their…
Q: A psychologist has tested 400 people on areas that make up the Sleepiness and Associated Sensations…
A: Here is a step-by-step guide on how to proceed with this analysis using JASP: Step 1: Import Data…
Q: A teacher claims that his students have an average social media usage that is different from 1.83…
A:
Q: The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level,…
A:
Step by step
Solved in 2 steps with 13 images
- A social psychologist recently developed a childhood-memories test that is intended to measure how people recall pleasant and unpleasant experiences from childhood. Scores on the test range from 1 (very unpleasant) to 100 (very pleasant). The psychologist standardized the test with a large group of college students (ages 18-25), and the mean score was p=60. The test was then given to a sample of n=25 individuals who were all between the ages of 40 and 45. The average score for this sample was 64.3 with SS (sum of squares)=600. Note: S?=SS÷df (variance is equal to sum of squares divided by the degrees of freedom). What is your conclusion if you were to test the hypothesis using one- tailed test at a=0.05? O a. Reject the null hypothesis O b. Fail to reject the null hypothesis O c. Accept the null hypothesis O d. None of the above2. In studying the effect of a drug for treating patients with respiratory problems, a researcher obtained a sample of 12 consenting patients, who, after discussion with their doctor, chose a respiratory drug they would receive. Patients' respiratory tests were assessed twice over a two-month period after initiating the treatment. Research question: The researcher wants to know if there is a significant difference between the group in their second test and those that didn't take the drug in their overall mean of 3.35 in average respiratory scores with a standard deviation of .08. Is there a difference between the two means - does the drug work? Carry out 9 steps of hypothesis testing. Respiratory Test 2 3.4 3.4 3.3 3.4 3.3 3.3 3.3 3.2 3.2 3.2 3.2 3.3 Σ-39.5An article reported the results of a peer tutoring program to help children learn to read. In the experiment, the children were randomly divided into two groups: the experimental group received peer tutoring along with regular instruction, and the control group received regular instruction with no peer tutoring. There were n1 = n2 = 30 children in each group. The Gates-MacGintie Reading Test was given to both groups before instruction began. For the experimental group, the mean score on the vocabulary portion of the test was x1 = 344.5, with sample standard deviation s1 = 49.5. For the control group, the mean score on the same test was x2 = 353.8, with sample standard deviation s2 = 50.9. Use a 5% level of significance to test the hypothesis that there was no difference in the vocabulary scores of the two groups before the instruction began. What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)
- Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 98.91, y = 99, r= 0.937, P-value = 0.000, and y = 5.67 + 0.94x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 95? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)A social psychologist recently developed a childhood-memories test that is intended to measure how people recall pleasant and unpleasant experiences from childhood. Scores on the test range from 1 (very unpleasant) to 100 (very pleasant). The psychologist standardized the test with a large group of college students (ages 18-25), and the mean score was p=60. The test was then given to a sample of n=25 individuals who were all between the ages of 40 and 45. The average score for this sample was 64.3 with SS (sum of squares)=600. Note: S?=SS÷df (variance is equal to sum of squares divided by the degrees of freedom). If you were to test the hypothesis using one-tailed test at a=0.05, what is the difference between group of scores using Cohen's d? O a. medium O b. small O c. large O d. none at allStudents in a representative sample of 65 first-year students selected from a large university in England participated in a study of academic procrastination. Each student in the sample completed the Tuckman Procrastination Scale, which measures procrastination tendencies. Scores on this scale can range from 16 to 64, with scores over 40 indicating higher levels of procrastination. For the 65 first-year students in this study, the mean score on the procrastination scale was 37.2 and the standard deviation was 6.41. USE SALT (a) Construct a 95% confidence interval estimate of μ, the mean procrastination scale for first-year students at this college. (Round your answers to three decimal places.) (b) Based on your interval, is 40 a plausible value for the population mean score? O Yes O No What does this imply about the population of first-year students? O This implies that on average, students at this university do have high levels of procrastination. O This implies that students at this…
- This is a friendly reminder about scientific notation. Excel reports very small numbers in scientific notation. For example, 8.15E-05 is typical notation for 8.15 x 10-5. The exponent of -5 means you have to move the decimal five places to the left and fill in with zeroes. What you get is 0.0000815. Here is the Excel output again for the regression of Sales and Experience: Regression Statistics 0.5966 0.3559 0.339 497.9058 Multiple R R Square Adjusted R Square Standard Error Observations ANOVA Regression Residual Total Intercept Experience (months) 40 df 1 38 39 Coefficients 6.6108 SS MS 5205388.04 5205388.04 9420585.51 Standard Error 4250.9742 180.2332 14625973.55 1.4427 247910.15 t Stat 23.586 4.5822 P-value 2.71E-24 4.85E-05 F 20.9971 Lower 95% Upper 95% Significance F 4.85E-05 3886.1113 4615.8372 3.6902 The analyst decides to use an a = 0.05 significance level. Is there a statistically significant relationship between Sales and Experience? 9.5313An article reported the results of a peer tutoring program to help children learn to read. In the experiment, the children were randomly divided into two groups: the experimental group received peer tutoring along with regular instruction, and the control group received regular instruction with no peer tutoring. There were n1 = n2 = 30 children in each group. The Gates-MacGintie Reading Test was given to both groups before instruction began. For the experimental group, the mean score on the vocabulary portion of the test was x1 = 344.5, with sample standard deviation s1 = 49.7. For the control group, the mean score on the same test was x2 = 353.8, with sample standard deviation s2 = 50.1. Use a 5% level of significance to test the hypothesis that there was no difference in the vocabulary scores of the two groups before the instruction began. (a) What is the level of significance?State the null and alternate hypotheses. H0: ?1 = ?2; H1: ?1 ≠ ?2H0: ?1 = ?2; H1: ?1 < ?2 H0: ?1 =…Dr. Springer collected data to see whether people who eat an all-carbohydrate meal have different scores on a mood scale than people who eat an all-protein meal. Higher scores represent better moods. Here are her results: All Carbs All Protein 10 7 8 4 7 9 9 28 13 13 7 7 12 Is there a difference in reported mood between the two groups? Use a two tailed test with an a = 0.05. Step 4: Make a decision Our test statistic has a value of t = I , and in Step 2 we found that the critical value is t* = the null hypothesis Therefore, we (write: reject or fail to reject)
- 3. A researcher was interested in the effects of a drug on depression. Subjects were randomly assigned to one of the three groups. Subjects in the control group received a placebo and the subjects in the two treatment groups received either a 0.2 mg or a 0.4 mg dosage of the drug. After several weeks of drug (or placebo) treatment, the researcher measured the subjects' level of depression (a low score indicating greater depression) The following data were obtained. Placebo 0.2 mg 0.4 mg 12 11 12 10 9. 14 11 11 17 13 13 16 15 7 16 12 Mean of X = 10 14 12 S^2 = 5.6 8.4 Using 5% of significance, test the hypothesis that the three groups differ in their effectiveness.An article reported the results of a peer tutoring program to help children learn to read. In the experiment, the children were randomly divided into two groups: the experimental group received peer tutoring along with regular instruction, and the control group received regular instruction with no peer tutoring. There were n1 = n2 = 36 children in each group. The Gates-MacGintie Reading Test was given to both groups before instruction began. For the experimental group, the mean score on the vocabulary portion of the test was x1 = 344.5, with sample standard deviation s1 = 45.5. For the control group, the mean score on the same test was x2 = 334.3, with sample standard deviation s2 = 48.5. Use a 10% level of significance to test the hypothesis that there was no difference in the vocabulary scores of the two groups before the instruction began. (a) What is the level of significance?State the null and alternate hypotheses. H0: ?1 = ?2; H1: ?1 > ?2H0: ?1 = ?2; H1: ?1 < ?2 H0: ?1 ≠…Question #2 A diet guide claims that you will get 120 calories in a serving of vanilla yogurt. Consumer Reports tested 14 brands of vanilla yogurt and found the following numbers of calories per serving: 160 200 220 230 120 180 140 130 170 190 80 120 100 170 Test the claim that the mean number of calories per serving of vanilla yogurt is 120. Use a significance level of 0.05. Show all the steps of your hypothesis test including The claim being tested: The null and alternative hypothesis: The test statistic