An experiment consists of tossing a single die and observing the number of dots that show on the upper face. Use events A, B, and C, defined as follows, to answer the question. A: observe a number less than 5 B: observe a number less than or equal to 3 C: observe a number greater than 4 Refer to the following probabilities. P(S) = 1 P(A|B) = 1 P(B) = P(An Bn C) = 0 P(An B) = P(An C) = 0 P(Bn C) = 0 P(AUC) = 1 5 P(BUC) = / Are events A and C independent? Since ---Select--- A and C ---Select--- Are events A and C mutually exclusive? Since--Select--- ✓, A and C ---Select--- mutually exclusive. independent.
An experiment consists of tossing a single die and observing the number of dots that show on the upper face. Use events A, B, and C, defined as follows, to answer the question. A: observe a number less than 5 B: observe a number less than or equal to 3 C: observe a number greater than 4 Refer to the following probabilities. P(S) = 1 P(A|B) = 1 P(B) = P(An Bn C) = 0 P(An B) = P(An C) = 0 P(Bn C) = 0 P(AUC) = 1 5 P(BUC) = / Are events A and C independent? Since ---Select--- A and C ---Select--- Are events A and C mutually exclusive? Since--Select--- ✓, A and C ---Select--- mutually exclusive. independent.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:An experiment consists of tossing a single die and observing the number of dots that show on the upper face. Use events A, B, and C, defined as follows, to answer the question.
A: observe a number less than 5
B: observe a number less than or equal to 3
C: observe a number greater than 4
Refer to the following probabilities.
P(S) = 1
P(AIB)
P(B)
P(An B)
= 1
P(BU C)
Since ---Select---
P(A n B n C) = 0
1
=
=
HNO
=
1
P(An C)
P(B n C)
0
P(AUC) = 1
5
6
=
2
NO
2
0
Are events A and C independent?
A and C ---Select--- independent.
Are events A and C mutually exclusive?
Since ---Select---
A and C ---Select--- mutually exclusive.
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