An engineer wants to know if producing metal bars using a new experimental treatment rather than the conventional treatment makes a difference in the tensile strength of the bars​ (the ability to resist tearing when pulled​ lengthwise). At α=0.20​, answer parts​ (a) through​ (e). Assume the population variances are equal and the samples are random. If​ convenient, use technology to solve the problem.   Treatment Tensile strengths (newtons per square millimeter) Experimental 411 376 386 441 443 379 410                      Conventional 379 380 357 420 412 378 397 392 425 369         ​(a) Identify the claim and state H0 and Ha.   The claim is​ "The new treatment ▼   makes a difference does not make a difference in the tensile strength of the​ bars." What are H0 and Ha​?   The null​ hypothesis, H0​, is ▼   mu 1 equals mu 2μ1=μ2 mu 1 less than or equals mu 2μ1≤μ2 mu 1 greater than or equals mu 2μ1≥μ2 . The alternative​ hypothesis, Ha​, is ▼   mu 1 not equals mu 2μ1≠μ2 mu 1 greater than mu 2μ1>μ2 mu 1 less than mu 2μ1<μ2 . Which hypothesis is the​ claim?     The alternative​ hypothesis, Ha   The null​ hypothesis, H0 ​(b) Find the critical​ value(s) and identify the rejection​ region(s).   Enter the critical​ value(s) below.   nothing ​(Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as​ needed.) Select the correct rejection​ region(s) below.   A. t>t0   B. −t0t0   D. t<−t0 ​(c) Find the standardized test statistic.   t=nothing ​(Type an integer or decimal rounded to the nearest thousandth as​ needed.) ​(d) Decide whether to reject or fail to reject the null hypothesis.   ▼   Fail to reject Reject the null hypothesis. ​(e) Interpret the decision in the context of the original claim.   At the 20% significance​ level, ▼   there is not there is enough evidence to support the claim.

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Chapter1: Starting With Matlab
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An engineer wants to know if producing metal bars using a new experimental treatment rather than the conventional treatment makes a difference in the tensile strength of the bars​ (the ability to resist tearing when pulled​ lengthwise). At
α=0.20​,
answer parts​ (a) through​ (e). Assume the population variances are equal and the samples are random. If​ convenient, use technology to solve the problem.
 
Treatment Tensile strengths (newtons per square millimeter)
Experimental
411 376 386 441 443 379 410                  
   
Conventional
379 380 357 420 412 378 397 392 425 369
 
 
 
 
​(a) Identify the claim and state
H0
and
Ha.
 
The claim is​ "The new treatment
 
makes a difference
does not make a difference
in the tensile strength of the​ bars."
What are
H0
and
Ha​?
 
The null​ hypothesis,
H0​,
is
 
mu 1 equals mu 2μ1=μ2
mu 1 less than or equals mu 2μ1≤μ2
mu 1 greater than or equals mu 2μ1≥μ2
.
The alternative​ hypothesis,
Ha​,
is
 
mu 1 not equals mu 2μ1≠μ2
mu 1 greater than mu 2μ1>μ2
mu 1 less than mu 2μ1<μ2
.
Which hypothesis is the​ claim?
 
 
The alternative​ hypothesis, Ha
 
The null​ hypothesis, H0
​(b) Find the critical​ value(s) and identify the rejection​ region(s).
 
Enter the critical​ value(s) below.
 
nothing
​(Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as​ needed.)
Select the correct rejection​ region(s) below.
 
A.
t>t0
 
B.
−t0<t<t0
 
C.
t<−t0, t>t0
 
D.
t<−t0
​(c) Find the standardized test statistic.
 
t=nothing
​(Type an integer or decimal rounded to the nearest thousandth as​ needed.)
​(d) Decide whether to reject or fail to reject the null hypothesis.
 
 
Fail to reject
Reject
the null hypothesis.
​(e) Interpret the decision in the context of the original claim.
 
At the
20%
significance​ level,
 
there is not
there is
enough evidence to support the claim.
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