### Educational Website Transcription---**Torque Calculation Exercise**An engineer applies a force of magnitude \( F = 15 \, \text{N} \) to the tip of a vertical lever. The force has an angle of \( 60^\circ \) with respect to the horizontal, as shown in the diagram below. The distance between point \( O \) and the tip of the lever is \( L = 0.25 \, \text{m} \).**Objective:**Determine the torque exerted by the force \( F \) with respect to an axis that is perpendicular to the plane of the page and passes through point \( O \). Express your answer in Newton-meters (Nm). Make sure to specify the direction of the torque by indicating if it points into the page or out of the page.**Diagram Description:**- A vertical lever is drawn, with point \( O \) at the bottom.- The length of the lever \( L \) is indicated as \( 0.25 \, \text{m} \).- Force \( F \) acts on the tip of the lever at an angle of \( 60^\circ \) from the horizontal.- A curved arrow denotes the direction and angle of the applied force.---Calculate the torque using the formula:\[ \tau = F \cdot L \cdot \sin(\theta) \]where \( \tau \) is the torque, \( F \) is the force, \( L \) is the lever arm length, and \( \theta \) is the angle between the force vector and the lever arm.

Answered: Image /qna-images/answer/10d00039-2236-4e3a-8b4e-d27e70fc0756.jpgr= perpendicular distance between force and axis of rotation.Hope it helps ?

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Physics

An engineer applies a force of magnitude F=15 N to the tip of a vertical lever. The force has an angle of 60° with respect to the horizontal, as shown in the image below. The distance between point O and the tip of the lever is L-0.25 m. Determine the torque exerted by the force F with respect to an axis that is perpendicular to the plane of the page and that passes through point O. Express your answer in Nm. Make sure you specify in your paper the direction of the torque by indicating if it points into the page or out of the page.

An engineer applies a force of magnitude F=15 N to the tip of a vertical lever. The force has an angle of 60° with respect to the horizontal, as shown in the image below. The distance between point O and the tip of the lever is L-0.25 m. Determine the torque exerted by the force F with respect to an axis that is perpendicular to the plane of the page and that passes through point O. Express your answer in Nm. Make sure you specify in your paper the direction of the torque by indicating if it points into the page or out of the page.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

Question

### Educational Website Transcription

---

**Torque Calculation Exercise**

An engineer applies a force of magnitude \( F = 15 \, \text{N} \) to the tip of a vertical lever. The force has an angle of \( 60^\circ \) with respect to the horizontal, as shown in the diagram below. The distance between point \( O \) and the tip of the lever is \( L = 0.25 \, \text{m} \).

**Objective:**
Determine the torque exerted by the force \( F \) with respect to an axis that is perpendicular to the plane of the page and passes through point \( O \). Express your answer in Newton-meters (Nm). Make sure to specify the direction of the torque by indicating if it points into the page or out of the page.

**Diagram Description:**
- A vertical lever is drawn, with point \( O \) at the bottom.
- The length of the lever \( L \) is indicated as \( 0.25 \, \text{m} \).
- Force \( F \) acts on the tip of the lever at an angle of \( 60^\circ \) from the horizontal.
- A curved arrow denotes the direction and angle of the applied force.

---

Calculate the torque using the formula:
\[ \tau = F \cdot L \cdot \sin(\theta) \]
where \( \tau \) is the torque, \( F \) is the force, \( L \) is the lever arm length, and \( \theta \) is the angle between the force vector and the lever arm.

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