In statics, the net torque is zero, and there is no angular acceleration. In rotational motion, net torque is the cause of angular acceleration, exactly as in Newton's second law of motion for rotation. Axis Hoop about cylinder axis Axis Annular cylinder (or ring) about cylinder axis I= MR Axis Solid cylinder (or disk) about cylinder axis Axis Solid cylinder (or disk) about central diameter MR2 MR + M 12 %3D Axis Axis Thin rod about Thin rod about axis through center 1 to length axis through one end I to length 12 Axis Axis Thin Solid sphere 2R about any diameter 2A spherical shell about any diameter 2MR Axis Axis Slab about I axis through Hoop about any diameter center MR2 M (a2 + b2) 12
In statics, the net torque is zero, and there is no angular acceleration. In rotational motion, net torque is the cause of angular acceleration, exactly as in Newton's second law of motion for rotation. Axis Hoop about cylinder axis Axis Annular cylinder (or ring) about cylinder axis I= MR Axis Solid cylinder (or disk) about cylinder axis Axis Solid cylinder (or disk) about central diameter MR2 MR + M 12 %3D Axis Axis Thin rod about Thin rod about axis through center 1 to length axis through one end I to length 12 Axis Axis Thin Solid sphere 2R about any diameter 2A spherical shell about any diameter 2MR Axis Axis Slab about I axis through Hoop about any diameter center MR2 M (a2 + b2) 12
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
Starting with the formula for the moment of inertia of a rod rotated around an axis through one end perpendicular to its length ( I = Mℓ 2 / 3) , prove that the moment of inertia of a rod rotated about an axis through its center perpendicular to its length is I = Mℓ 2 / 12 . You will find the graphics in Figure shown useful in visualizing these rotations.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 7 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON