An electron of kinetic energy 1.20 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 25.0 cm. Find (a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion.
Q: An oxygen nucleus (8 protons, 8 neutrons) moves at a velocity of 2.48 x 10^6 m/s in a direction…
A: Velocity, v = 2.48 x 10^6 m/s Radius, R = 3.44 cm = 3.44×10-2 mCharge, q = 8eMass of nucleus, m =…
Q: Problem 7: An alpha particle (consisting of two protons and two neutrons), traveling at a speed of…
A: Particle : Alpha particle Number of protons = 2 Number of neutrons = 2 Speed (v) = 1.4×105…
Q: An electron of kinetic energy 1.15 keV circles in a plane perpendicular to a uniform magnetic field.…
A: Conversion unit : 1eV=1.6×10-19J 1m=100 cm 1 Kg=1000 gms given: K.E of electron =1.15…
Q: he vector magnetic force acting.
A: Current carried by first long wire I1=28ACurrent carried by first long wire I2=64A
Q: An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of…
A:
Q: A double-ionized helium atom, carrying charge +2e (a-particle) is moving with velocity v, that makes…
A: Given that the charge carried by the particle is +2e, e being the magnitude of electronic charge,…
Q: An alpha-particle (m = 6.64 × 10−27 kg, q = 3.2 × 10−19 C) travels in a circular path of radius 25…
A: Consider B denotes the magnetic field strength which is given as 1.5 T. Let r denote the radius of…
Q: A) A particle, with charge +2 µC, moving (along -z axis) with the speed 5.0 x 105 m/s enters in a…
A: The force on a charge inside a magnetic field is given by: F =qvBsinθθ = angle between the velocity…
Q: A proton is launched with a speed of 2.80 x 106 m/s perpendicular to a uniform magnetic field of…
A:
Q: A wire is formed into a circle having a diameter of 12.0 cm and placed in a uniform magnetic field…
A: diameter (d) = 12 cm radius (r) = 12 cm2= 6 cm = 0.06 m magnetic field (B) = 3.10 mT B = 0.0031 T…
Q: An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of…
A: we know that
Q: (a) An electron moves through a uniform electric field E = (2.201 + 4.80ĵ) V/m and a uniform…
A:
Q: (a) An electron moves through a uniform electric field E (2.00 +4.605) V/m and a uniform magnetic…
A:
Q: An electron of kinetic energy 1.66 keV circles in a plane perpendicular to a uniform magnetic field.…
A: Given that:- Kinetic energy of electron=1.66KeV Radius of circle=21.2cm
Q: An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of…
A:
Q: A proton is launched with a speed of 2.90 x 106 m/s perpendicular to a uniform magnetic field of…
A: Given dataThe speed of the proton is given as vp = 2.90 x 106 m/s.The uniform magnetic field is…
Q: A monoenergetic (18 keV) electron beam initially in the horizontal direction is subjected to a…
A: Basic Details The kinetic energy of the electron depends on the mass of the electron and the speed…
Q: A proton moves along the y-axis with vy = -4.05E+6 m/s. As it passes the origin, what is the…
A: Given,velocity of the proton, v→ = -4.05×106 j^ msfind :The magnetic field strength at the point x,…
Q: Positively charged ions, with unknown charge magnitude, initially at rest, are accelerated through…
A:
Q: An electron that is accelerated from rest through a potential of 4.00 kV enters the velocity filter,…
A: Given that, Potential difference, V = 4kV Electric field between parallel plate capacitor, E = 7.80…
Q: (a) An electron moves through a uniform electric field E = (2.801 + 5.80J) V/m and a uniform…
A:
Q: An electron of kinetic energy 1.60 keV circles in a plane perpendicular to a uniform magnetic field.…
A:
Q: An electron of kinetic energy 1.62 keV circles in a plane perpendicular to a uniform magnetic field.…
A:
Q: An electron of kinetic energy 1.78 keV circles in a plane perpendicular to a uniform magnetic field.…
A:
Q: A proton describes a circular orbit of radius 27 cm perpendicular to a magnetic field of modulus 1.0…
A:
Q: A galaxy in a cluster has a crossing time of 2.3 Gyr. Given that the diameter of the cluster is 2.5…
A: Approach to solving the question: Detailed explanation: Examples: Key references:
Q: An unknown particle travelling with a velocity of 3.12 x 105 m/s enters a 54 mT magnetic field and…
A:
Q: A particle having mass m = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is…
A: particle having mass m = 2.80E-4 kg negative charge q= −1.70E-6 C . The particle is given an…
Step by step
Solved in 3 steps
- An alpha-particle (m = 6.64·10−27 kg; q = 3.2·10−19 C) travels in a circular path of radius 28 cm in a uniform magnetic field of magnitude 1.3 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?An electron is launched at a speed of v at an angle of 0 north of east into a region with a uniform magnetic field. The magnitude of the magnetic field is B and the field is pointing due east. a) Find the radius of curvature of the trajectory. b) Find the pitch (the distance traveled during one revolution, perpendicular to the plane of circular motion) of the trajectory.A proton is moving in a circular orbit of radius 28.9 cm with a speed of 3.7*106m/s in a uniform magnetic field perpendicular to the velocity of the proton. Find the magnetic field in which the proton is moving. mp = 1.67×10-27 kg, charge of proton = 1.61×10-19C. Also calculate the time period of the proton. Calculate the magnetic field and the time period to two decimal places. Submit the magnetic field as your answer. You are required to show your work in the file you submit.
- An electron of kinetic energy 1.74 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 31.2 cm. Find (a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion. (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i UnitsAn electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 1.98 mT. If the speed of the electron is 1.40 x 107 m/s, determine the following. (a) the radius of the circular path cm (b) the time interval required to complete one revolutionAn electron of kinetic energy 1.29 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 21.8 cm. Find (a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion. (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i Units
- An electron moves in a circle of radius r = 5.50 × 10-11 m with a speed 1.97 × 106 m/s. Treat the circular path as a current loop with a constant current equal to the ratio of the electron's charge magnitude to the period of the motion. If the circle lies in a uniform magnetic field of magnitude B = 6.68 mT, what is the maximum possible magnitude of the torque produced on the loop by the field?An electron that has velocity т i = (2.0 x 106)i+ (3.0 × 106 10", %3D moves through the uniform magnetic field B = (0.030 T)î – (0.15T)f. (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity.An evacuated long tube contains a beam of electrons. The tube terminates on the center of a face of a cubic region in which there is a uniform magnetic field perpendicular to the tube. If the electrons exit from the center of an adjacent face of the cube (not the opposite face), what speed must the electrons have if the field strength is 45.0 gauss? Please include a diagram for the problem.