An unknown particle travelling with a velocity of 3.12 x 105 m/s enters a 54 mT magnetic field and curves in a circular path with a radius of 12 cm. Determine the charge-to-mass ratio, enter that value in the first blank (with three significant figures of accuracy). From the table of particles on your data sheet (showing data for the charge and mass for alpha particle, electron, proton, and neutron), the identity of the unknown particle is most likely.

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Chapter1: Units, Trigonometry. And Vectors
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Alberta Education, Provincial
Assessment
Sector
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57
Physics 30
Constants
Acceleration Due to Gravity
Near Earth..
Gravitational Constant
Radius of Earth
Mass of Earth....
Elementary Charge..........
Coulomb's Law Constant..
Electron Volt.......
Index of Refraction of Air.
Speed of Light in Vacuum.
Planck's Constant........
|ag|= 9.81 m/s²
G=6.67 x 10-¹1 N-m²/kg²
re= 6.37 x 106 m
M₂ = 5.97 x 10²4 kg
e = 1.60 x 10-19 C
k=8.99 x 10° N-m²/C²
1 eV = 1.60 x 10-19 J
n = 1.00
c = 3.00 x 108 m/s
h = 6.63 x 10-34 J.S
h=4.14 x 10-15 eV-s
Atomic Mass Unit .............. u= 1.66 x 10-27 kg
Physics Principles
0 Uniform motion (Fnet = 0)
1 Accelerated motion (Fnet * 0)
2
Uniform circular motion (Fnet is radially inward)
Work-energy theorem
3
4 Conservation of momentum
5 Conservation of energy
6 Conservation of mass-energy
7 Conservation of charge
8 Conservation of nucleons
9 Wave-particle duality
PHYSICS DATA SHEET
Prefixes Used with SI Units
Prefix Symbol
atto
a.
femto........... f
pico. p.....
n.......
nano..
micro
milli.
centi.
deci.
deka
hecto
kilo
mega
giga.
tera...
μl
m
с
d.
da.
h..
k.
M
G.
T
Exponential
Value
10-18
10-15
10-12
10-9
10-6
10-3
10-²
10-¹
.10¹
10²
10³
106
10⁹
10¹2
Particles
Alpha Particle...
Electron..
Proton.
Neutron......
First-Generation Fermions
Electron.
Charge
+2e
Positron
- le
+le
0
Charge
- le
+le
Electron neutrino, v........
0
Electron antineutrino, V........ 0
Up quark, u........
Anti-up antiquark, u...............
Down quark, d..
Anti-down antiquark, d..........
+
*NEW
Mass
6.65 x 10-27 kg
9.11 x 10-31 kg
1.67 x 10-27 kg
1.67 x 10-27
Mass
kg
~0.511 MeV/c²
~0.511 MeV/c²
<2.2 eV/c²
< 2.2 eV/c²
-2.4 MeV/c²
-2.4 MeV/c²
~4.8 MeV/c²
-4.8 MeV/c²
Transcribed Image Text:Alberta Education, Provincial Assessment Sector To go back after using an internal link, simultaneously press and hold Alt (in some browsers). 57 Physics 30 Constants Acceleration Due to Gravity Near Earth.. Gravitational Constant Radius of Earth Mass of Earth.... Elementary Charge.......... Coulomb's Law Constant.. Electron Volt....... Index of Refraction of Air. Speed of Light in Vacuum. Planck's Constant........ |ag|= 9.81 m/s² G=6.67 x 10-¹1 N-m²/kg² re= 6.37 x 106 m M₂ = 5.97 x 10²4 kg e = 1.60 x 10-19 C k=8.99 x 10° N-m²/C² 1 eV = 1.60 x 10-19 J n = 1.00 c = 3.00 x 108 m/s h = 6.63 x 10-34 J.S h=4.14 x 10-15 eV-s Atomic Mass Unit .............. u= 1.66 x 10-27 kg Physics Principles 0 Uniform motion (Fnet = 0) 1 Accelerated motion (Fnet * 0) 2 Uniform circular motion (Fnet is radially inward) Work-energy theorem 3 4 Conservation of momentum 5 Conservation of energy 6 Conservation of mass-energy 7 Conservation of charge 8 Conservation of nucleons 9 Wave-particle duality PHYSICS DATA SHEET Prefixes Used with SI Units Prefix Symbol atto a. femto........... f pico. p..... n....... nano.. micro milli. centi. deci. deka hecto kilo mega giga. tera... μl m с d. da. h.. k. M G. T Exponential Value 10-18 10-15 10-12 10-9 10-6 10-3 10-² 10-¹ .10¹ 10² 10³ 106 10⁹ 10¹2 Particles Alpha Particle... Electron.. Proton. Neutron...... First-Generation Fermions Electron. Charge +2e Positron - le +le 0 Charge - le +le Electron neutrino, v........ 0 Electron antineutrino, V........ 0 Up quark, u........ Anti-up antiquark, u............... Down quark, d.. Anti-down antiquark, d.......... + *NEW Mass 6.65 x 10-27 kg 9.11 x 10-31 kg 1.67 x 10-27 kg 1.67 x 10-27 Mass kg ~0.511 MeV/c² ~0.511 MeV/c² <2.2 eV/c² < 2.2 eV/c² -2.4 MeV/c² -2.4 MeV/c² ~4.8 MeV/c² -4.8 MeV/c²
An unknown particle travelling with a velocity of 3.12 x 105 m/s enters a 54 mT
magnetic field and curves in a circular path with a radius of 12 cm.
Determine the charge-to-mass ratio, enter that value in the first blank (with three
significant figures of accuracy).
From the table of particles on your data sheet (showing data for the charge and mass
for alpha particle, electron, proton, and neutron), the identity of the unknown
particle is most likely.
Transcribed Image Text:An unknown particle travelling with a velocity of 3.12 x 105 m/s enters a 54 mT magnetic field and curves in a circular path with a radius of 12 cm. Determine the charge-to-mass ratio, enter that value in the first blank (with three significant figures of accuracy). From the table of particles on your data sheet (showing data for the charge and mass for alpha particle, electron, proton, and neutron), the identity of the unknown particle is most likely.
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