An electron moves at 2.00 x 10° m/s through aPart Aregion in which there is a magnetic field ofunspecified direction and magnitude7.40 x 10-2 T.What is the largest possible magnitude of the acceleration of the electron due to the magnetic field?Express your answer with the appropriate units.?ValueUnitsa =Part BWhat is the smallest possible magnitude of the acceleration of the electron due to the magnetic field?Express your answer with the appropriate units.HÀ?ValueUnitsa = Part CIf the actual acceleration of the electron is one-fourth of the largest magnitude in part A, what is the anglebetween the electron velocity and the magnetic field?Express your answer in degrees to three significant figures.ΑΣφII

Electron velocity v = 2.00 × 106 m/s Magnetic field B = 7.40 × 10- 2 T

Answered: An electron moves at 2.00 x 10 m/s…

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