Part AAt a particular instant, charge q1 = 4.50x10-6 C isat the point (0, 0.250 m, 0) and has velocity(9.20 × 105 m/s) î. Charge q2 =-2.60x10-6 C is at the point (0.150 m, 0, 0) andhas velocity v2 =At this instant, what is the magnetic force that qi exerts on q2?Express your answers in micronewtons separated by commas.(-5.30 x 105 m/s) j.Hν ΑΣφ?KITAΣФΩFa, Fy, F; =µN%3DSubmitPrevious Answers Request AnswerX Incorrect; Try Again圓

Answered: Image /qna-images/answer/b5c3805e-1b6e-4c39-be03-d6f74fbd796e.jpg

Part A At a particular instant, charge qı = 4.50x10-6 C is at the point (0, 0.250 m, 0) and has velocity = (9.20 × 105 m/s) î . Charge q2 = -2.60x10-6 C is at the point (0.150 m, 0, 0) and has velocity v2 = (-5.30 × 105 m/s) j. At this instant, what is the magnetic force that qı exerts on q2 ? Express your answers in micronewtons separated by commas. Πν ΑΣφ ? a K A Σ F2, Fy, F; = µN Submit Previous Answers Request Answer X Incorrect; Try Again

Part A At a particular instant, charge qı = 4.50x10-6 C is at the point (0, 0.250 m, 0) and has velocity = (9.20 × 105 m/s) î . Charge q2 = -2.60x10-6 C is at the point (0.150 m, 0, 0) and has velocity v2 = (-5.30 × 105 m/s) j. At this instant, what is the magnetic force that qı exerts on q2 ? Express your answers in micronewtons separated by commas. Πν ΑΣφ ? a K A Σ F2, Fy, F; = µN Submit Previous Answers Request Answer X Incorrect; Try Again

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A particle (m = 70 mg, q = -5.0 µC) %3D moves in a uniform electric field of 60 kN/C in the positive x-direction. At t = 0, the particle is moving 30 m/s in the positive x-direction and is passing through the origin. Determine the maximum distance beyond x = 0 the particle travels in the positive x- direction. Select one: A. 315.0 m B. 210.0 m C. 52.5 m D. 105.0 m
Consider the following. B 0.500 mm 60.0° (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 6.60 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? magnitude N/C direction ° counterclockwise from the +x axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The magnitude of the field would be doubled. O The field would be unchanged. O The magnitude of the field would be halved. O The magnitude of the field would be quadrupled.
The figure (Figure 1) shows a thin rod of length I with total charge Q. Figure L ++ P 1 of 1 Verify that your expression has the expected behavior if r > L Express your answer in terms of variables Q, r and constants , ED. E Submit Part C IVE ΑΣΦ a x² Xb√x x x X.10n E www 21.7.10³ Previous Answers Request Answer Evaluate E at r = 3.9 cm if L = 5.0 cm and Q = 2.6 nC. Express your answer with the appropriate units. * Incorrect; Try Again; 9 attempts remaining The correct answer involves the variable Q, which was not part of your answer. μÅ Value Submit Request Answer Units
An electron is traveling through a uniform electric field. The field is constant and given by E=(2.00×10−11N/C) i^− (1.20×10−11N/C) j^. At t=0 , the electron is at the origin and traveling in the x direction with a speed of 2.20 m/s. Part A) What is its position 2.50 s later? x= ? (in m) Part B) y=?
A positive charge of 4.20 μC is fixed in place. From a distance of 4.20 cm a particle of mass 6.20 g and charge +3.00 μC is fired with an initial speed of 62.0 m/s directly toward the fixed charge. How close to the fixed charge does the particle get before it comes to rest and starts traveling away? (in cm)
Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 45.1 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.78 cm, located a distance y= 58.7 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? 77.9 cm 41.9 cm 59.9 cm 30.0 cm
One type of ink-jet printer, called an electrostatic ink-jet printer, forms the letters by using deflecting electrodes to steer charged ink drops up and down vertically as the ink jet sweeps horizontally across the page. The ink jet forms 35.0 μm-diameter drops of ink, charges them by spraying 800,000 electrons on the surface, and shoots them toward the page with a horizontal velocity of 17.0 m/s. Along the way, the drops pass through the long axis of two horizontal, parallel electrodes that are 6.0 mm long, 4.0 mm wide, and spaced 1.0 mm apart. The distance from the center of the electrodes to the paper is 1.90 cm. To form the letters, which have a maximum height of 6.0 mm, the drops need to be deflected up or down a maximum of 3.0 mm. Ink, which consists of dye particles suspended in alcohol, has a density of 800 kg/m³. 3 E D 80 C $ 4 R 888 F4 F V % 5 FS T ^ G 6 B Part A What electric field strength is needed between the electrodes to achieve this deflection? Express your answer with…
Two 4.0 kgkg masses are 1.0 mm apart on a frictionless table. Each has 1.0 μCμC of charge. Part A What is the magnitude of the electric force on one of the masses? Part B What is the initial acceleration of each mass if they are released and allowed to move? Express your answer in meters per second squared.
A small plastic ball with a mass of 6.65 10-3 kg and with a charge of +0.149 µC is suspended from an insulating thread and hangs between the plates of a capacitor (see the drawing). The ball is in equilibrium, with the thread making an angle of 30.0° with respect to the vertical. The area of each plate is 0.0138 m2. What is the magnitude of the charge on each plate? C
Three charges are located as shown in the figure, with values q1 = 3.4 × 10-16 C, q2 = -1.9 × 10-16 C, q3 = 6.25 × 10-16 C. The charges are separated by d1 = 2.4 × 10-6 m and d2 = 2.4 × 10-6 m. a. What is the force of q2 on q1 in the x direction, Fx? Give your answer in newtons, and recall k = 8.988 × 109 N m2/C2. b. What is the force of q3 on q1 in the y direction, Fy? Give your answer in newtons.
Two m = 5.8 g point charges on 1.0-m-long threads repel each other after being charged to q = 80 nC, as shown in the figure. (Figure 1) Figure 1.0 m m + 9 00 1.0 m +m 9 1 of 1 Part A What is the angle 0? You can assume that is a small angle. Express your answer to two significant figures and include the appropriate units. μ 0 = 4.21 Submit μÅ Ω % À X Previous Answers Request Answer ? X Incorrect; Try Again; 7 attempts remaining
Consider the following. 60.0⁰ B 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C= -4.30 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction o counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The field would be unchanged. O The magnitude of the field would be doubled. O The magnitude of the field would be quadrupled. O The magnitude of the field would be halved.