An electron is orbiting a nucleus which has a charge of 14e, under the action of the Coulomb force at a radius of 1.14 × 10-10, m. Calculate the angular velocity of the electron, in radians per second. @=
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A: Given that: B=5.27 mT=5.27×10-3TL=4.09×10-26 kgm2/sKnown:q=1.6×10-19 Cm=9.1×10-31 kg
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A: Q=5.5 μc=5.5×10-6 Ca=1.8 nm=1.8×10-9 m
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- please help asap!= 1.602 × 19 = Problem 19.02. A molecule with mass m = 9.11 × 10-25 kg and net charge de 10-1⁹ C is accelerated from rest across a potential difference of V = 200 V. (a) What is the molecule's change in potential energy ¡U? (b) What is the molecule's final velocity vf?Consider the two charges in the figure, which are moving in opposite directions and located a distance 11 cm on either side of the origin of the given coordinate system. Charge one is 19.5 uC and is moving at a speed 19.5 x U2 10° m/s, and charge two is -8.5 µC and is moving at a speed of 6.5 x 106 m/s. Notice that the positive z-direction in this figure is directed out of the page. 92 d What is the total magnetic field, in the z-direction, at a point Q located a distance 45 cm down the x-axis, as shown? d 91
- only 7 and 8Use the following constants if necessary. Coulomb constant, k = 8.987 x 10° N m2 /C. Vacuum permitivity, eo = 8.854 x 10 12 F/m. Magnitude of the Charge of one electron, e =-1.60217662 x 10-19 C. Mass of one electron, m, = 9.10938356 x 10-31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, uC means micro coulomb. Y R. Suppose you have 5 point charges q to q, distributed along a semi-circle maintaining equal distance. The charge q6 is on the center of the circle which is also the origin of given coordinate system. The radius of the semi-circle is R = 34 cm and the magnitude of the charges are as follows : 91 = = 19 µC, q2 = q4 = 32 µC and q = q6 = -25 µC. a) Find the vector that points from q to g6 and call it F1,6- b) Calculate the coulomb force on g6 due to q in unit vector notation and call it F16 c) Find the vector that points from q3 to g6 and call it F3,6- d) Calculate the coulomb force on q6 due to g in unit vector notation and call it F36. e)…An alpha particle (charge 2e) is aimed directly at a gold nucleus(charge 79e). What minimum initial kinetic energy must the alphaparticle have to approach within 7.0 * 10-14 m of the center of thegold nucleus before reversing direction? Assume that the gold nucleus,which has about 40 times the mass of an alpha particle, remains at rest.
- The ball of mass m = 2.00 g has a drag coefficient of D = 0.500 and a radius of r = 1.00 cm, and carries a charge of 3.75 µC. The density of air surrounding the ball is ) = 1.20 kg/m. Divide your group in two and have one subgroup solve part (a) and the other part (b). (a) Group (i): The wind blows to the right in the figure at a speed of 10.0 m/s. What angle (in degrees) does the string make with the vertical? (b) Group (ii): The wind shifts so that it blows into the page at the same speed. Now what angle (in degrees) does the string make with the vertical? Now gather your group together again and answer the following. (c) In part (b), what angle (in degrees) does the string make with the plane of the page when looking at the figure?(b) The magnitude of the electrostatic force between the proton and electron in a hydrogen atom is Fg. The magnitude of the gravitational force between them is Fg. FE Determine the ratio . FGWhat is the magnitude of the repulsive force between a 3.4 mC charge and a 6.3 mC charge if they are separated by a distance of 93 centimeters? Report your answer kN rounded up to the tenths place
- A hydrogen atom is located close to the surfsce of the earth. a) What is the ratio of the magnitude of the electric force between the electron and proton compared to the magnitude of the gravitational attraction between the electron and proton compared to the magnitude of the gravitational attraction between the electron and the earth? (This is how many times greater the electric force is in this situation) b) Draw a conclusion about the stability of matter. (How come gravity doesn't pull molecules apart?) c) Why is the gravitational force between the Earth and Moon greater than the electric force? (Since all matter is made of protons and electrons, why isn't electric force always greater?)A point charge for which Q = 4.2 × 10-16 C and m = 2.5 x 10-26 kg is moving in the combined fields E = 250ax + 115ay - 230a, V/m and B = 2ax - ay - 3a, mT. If the charge velocity at t = 0 is v(0) = (2ax + 4ay +3az) × 105 m/s: %3D give the unit vector showing the direction in which the charge is accelerating at t = 0. find the kinetic energy of the charge at t = 0. Answers: a. Blank 1ax + Blank 2ay + Blank 3 az b. Blank 4 fJCalculate the angular velocity ω of an electron orbiting a proton in an atom, assuming the radius of the orbit is 5.02×10^-11 m. You may assume that the proton is stationary and the centripetal force is supplied by Coulomb attraction.