An electron in the H atom moves from an unknown energy level to n= 2. The energy reloased in this process is 291.6 kJ/mol. (NA = 6.022 x 1023 moF) (1) Identify the unknown energy level. Show your calculations.

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An electron in the H atom moves from an unknown energy level to n= 2. The energy
reloased in this process is 291.6 kJ/mol.
(NA = 6.022 x 1023 moF)
(1) Identify the unknown energy level. Show your calculations.
Transcribed Image Text:An electron in the H atom moves from an unknown energy level to n= 2. The energy reloased in this process is 291.6 kJ/mol. (NA = 6.022 x 1023 moF) (1) Identify the unknown energy level. Show your calculations.
Expert Solution
Step 1

Energy released in the process of moving of electron from one energy level to another is given by,

                                                          Chemistry homework question answer, step 1, image 1

Where, ∆E  total energy released in the process in J

            RH is a constant = 2.179 x 10-18 J

            nf is final energy level

           ni is the initial energy level.

Now, the energy given is expressed as per mole.

So, total energy released is = Energy released per mole / NA

                                            = 291.6 kJ mol-1 / (6.022 x 1023 mol-1)

                                            = 4.84 x 10-22 kJ

                                            = 4.84 x 10-22 x 1000 J

                                            = 4.84 x 10-19 J

Again, as energy is released by the system, so ∆E will be negative, i.e.

                        ∆E = - 4.84 x 10-19 J

Part (i)

We have, nf = 2

Now, substituting the values in the above equation,

                         Chemistry homework question answer, step 2, image 1

Therefore, the unknown energy level is n = 6 .

 

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