An electric field of magnitude 5.25 x 105 N/C points due east at a certain location. Find the magnitude and direction of the force on a-4.55 μC charge at this location. magnitude direction ---Select--- ✓ N

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An electric field of magnitude \(5.25 \times 10^5 \, \text{N/C}\) points due east at a certain location. Find the magnitude and direction of the force on a \(-4.55 \, \mu \text{C}\) charge at this location.

- Magnitude: \(\_\_\_\_\) N
- Direction: [Select]
Transcribed Image Text:An electric field of magnitude \(5.25 \times 10^5 \, \text{N/C}\) points due east at a certain location. Find the magnitude and direction of the force on a \(-4.55 \, \mu \text{C}\) charge at this location. - Magnitude: \(\_\_\_\_\) N - Direction: [Select]
Expert Solution
Step 1

Given data: 

Electric field (E) = 5.25×105 N/C, due East 

Charge (q) = -4.55 μC

Required

The magnitude and direction of the force on the charge 

 

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