An electric field is restricted to a circular area of diameter d = 10.3 cm as shown in the figure. umogo tatou 9+ +V "out •P can DUC , 4+0+ IP PI tot op 4 pus
An electric field is restricted to a circular area of diameter d = 10.3 cm as shown in the figure. umogo tatou 9+ +V "out •P can DUC , 4+0+ IP PI tot op 4 pus
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![An electric field is restricted to a circular area of diameter d = 10.3 cm as shown in the figure.
"out
•P
At the instant shown, the field direction is out of the page, its magnitude is 300 V/m, and its magnitude is increasing at a
rate of 21.4 V/(m. s).
(a) What is the direction of the magnetic field at the point P, r = 15.1 cm from the center of the circle?
upwards
downwards
(b) What is the magnitude of the magnetic field (in T) at the point P, r = 15.1 cm from the center of the circle?
2.09*10**-17
X
Apply the extended form of Ampere's law. Note that I = 0 in this case. What is the electric flux? What is the rate of
change of the electric flux? T
(c) What If? As before, at the moment shown in the figure, the electric field within the circle has a magnitude of
300 V/m and is increasing at a rate of 21.4 V/(ms). In addition, suppose that the radius of the circular area of the
electric field increases at a rate of 1.00 cm/s. What would the magnitude of the magnetic field be at point P at this
moment (in T)?
1.347*10**-16 X
Follow the same procedure as in part (b), but note now the flux changes in both the magnitude of the electric field
and the area. How do you take this into account when finding the derivative of the flux? T](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7e8a00db-a29c-4687-9bee-3454cf3c949f%2F5e9453c4-60ca-4e3c-9065-1a372bbaf66e%2Frfqg6ov_processed.png&w=3840&q=75)
Transcribed Image Text:An electric field is restricted to a circular area of diameter d = 10.3 cm as shown in the figure.
"out
•P
At the instant shown, the field direction is out of the page, its magnitude is 300 V/m, and its magnitude is increasing at a
rate of 21.4 V/(m. s).
(a) What is the direction of the magnetic field at the point P, r = 15.1 cm from the center of the circle?
upwards
downwards
(b) What is the magnitude of the magnetic field (in T) at the point P, r = 15.1 cm from the center of the circle?
2.09*10**-17
X
Apply the extended form of Ampere's law. Note that I = 0 in this case. What is the electric flux? What is the rate of
change of the electric flux? T
(c) What If? As before, at the moment shown in the figure, the electric field within the circle has a magnitude of
300 V/m and is increasing at a rate of 21.4 V/(ms). In addition, suppose that the radius of the circular area of the
electric field increases at a rate of 1.00 cm/s. What would the magnitude of the magnetic field be at point P at this
moment (in T)?
1.347*10**-16 X
Follow the same procedure as in part (b), but note now the flux changes in both the magnitude of the electric field
and the area. How do you take this into account when finding the derivative of the flux? T
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