es Required information In gel electrophoresis, the mobility of a molecule in a particular gel matrix is defined as = v/E, where it is the terminal speed of the molecule and E is the applied electric field strength. In one case, a molecule has mobility 2.83 × 10-8 C-m/(N-s) and charge -12e. How long does it take the molecule to move 2.10 cm through the gel if the terminal speed of the molecule is 1.50 × 10-5 m/s? min Check my we
es Required information In gel electrophoresis, the mobility of a molecule in a particular gel matrix is defined as = v/E, where it is the terminal speed of the molecule and E is the applied electric field strength. In one case, a molecule has mobility 2.83 × 10-8 C-m/(N-s) and charge -12e. How long does it take the molecule to move 2.10 cm through the gel if the terminal speed of the molecule is 1.50 × 10-5 m/s? min Check my we
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Required information In gel electrophoresis, the mobility of a molecule in a particular gel matrix is defined as mu = u_{t} / E where is the terminal speed of the molecule and E is the applied electric field strengthIn one case, a molecule has mobility 2.83 * 10 ^ - 8; Cm / (Ns) and charge-12e How long does it take the molecule to move 210 cm through the gel if the terminal speed of the molecule 1.5 * 10 ^ - 5 * m / s ? min
![### Required Information
In gel electrophoresis, the mobility (µ) of a molecule in a particular gel matrix is defined as:
\[ \mu = \frac{v_t}{E} \]
where \( v_t \) is the terminal speed of the molecule and \( E \) is the applied electric field strength.
In one case, a molecule has a mobility of \( 2.83 \times 10^{-8} \) C•m/(N•s) and a charge of \(-12e\).
### Problem Statement
**Question:**
How long does it take the molecule to move 2.10 cm through the gel if the terminal speed of the molecule is \( 1.50 \times 10^{-5} \) m/s?
**Answer (to be provided by student):**
____ minutes](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b578b6a-d8d1-4da1-b505-9cebf317d6ed%2Ffbf5f7af-51fa-4531-8bed-fa9144e49860%2F9dvgbr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Required Information
In gel electrophoresis, the mobility (µ) of a molecule in a particular gel matrix is defined as:
\[ \mu = \frac{v_t}{E} \]
where \( v_t \) is the terminal speed of the molecule and \( E \) is the applied electric field strength.
In one case, a molecule has a mobility of \( 2.83 \times 10^{-8} \) C•m/(N•s) and a charge of \(-12e\).
### Problem Statement
**Question:**
How long does it take the molecule to move 2.10 cm through the gel if the terminal speed of the molecule is \( 1.50 \times 10^{-5} \) m/s?
**Answer (to be provided by student):**
____ minutes
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