HomaAn education researcher claims that 60% of college students work year-round. In a random sample of 300 college students, 180 say they work year-round. Ala=0.05, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below.O C. Atleast% of college students work year-round.bookOD. The percentage of college students who work year-round is not%.cer ContentsLet p be the population proportion of successes, where a success is a college student who works year-round. State Ho and H. Select the correct choice belowand fill in the answer boxes to complete your choice.(Round to two decimal places as needed.)O A. Ho p#GB. H, p=0.60media LibraryOC. Ho P<Ha p=H p 0.60Ha p2O D. Ho p2OE. Ho P>PlanOF. Ho psH, p<H3 psH p>Tor Success(b) Find the critical value(s) and identify the rejection region(s).sible ResourcesIdentify the critical value(s) for this test.for Success%3D(Round to two decimal places as needed. Use a comma to separate answers as needed.)Clear allCheck answerView an exampleGet more help-Help me solve thisCopyrightO 2021 Pearson Education inc. Allrights reserved. TermS OL Use PIvacy Policy T PermissionS Contact US60°F A OP Type here to search業DG521 AUXXL-BTY10/05/17DelInsertPrtScF12F11

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Answered: an education researcher claims that 60%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher belleves that 52% of people who grew up as the only child have an IQ score over 100. However, unknown to the researcher, this figure is actually 50%, which is the same as in the general population. To attempt to find evidence for the claim, the researcher is going to take a random sample of 400 people who grew up as the only child. Let p be the proportion of people in the sample with an IQ score above 100. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p. (b) Find the standard deviation of p. (c) Compute an approximation for P(p 20.52), which is the probability that there will be 52% or more people with IQ Scores over 100 in the sample. Round your answer to four decimal places. 2022 acer
It has been claimed that at UCLA at least 40% of the students live on campus. In a random sample of 250 students, 90 were found to live on campus. Does the evidence support the claim at = .01?
Español According to previous studies, 10% of the U.S. population is left-handed. Not knowing this, a high school student claims that the percentage of left-handed people in the U.S. is 12%. The student is going to take a random sample of 900 people in the U.S. to try to gather evidence to support the claim. Let p be the proportion of left-handed people in the sample. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p. 0.12 (b) Find the standard deviation of p. X 5 (c) Compute an approximation for P(p≤0.12), which is the probability that there will be 12% or fewer left-handed people in the sample. Round your answer to four decimal places. A 27
Statistics Question
Use the results from a survey of a simple random sample of 1108 adults. Among the 1108 respondents, 84% rated themselves as above average drivers. We want to test the claim that 3/4 of adults rate themselves as above average drivers. a. Identify the actual number of respondents who rated themselves as above average drivers.
A researcher wishes to determine whether there is a difference in the average age of elementary school, high school, and community college teachers. Teachers are randomly selected from each group. Their ages are recorded below. Test the claim that at least one mean is different from the others. Use α = 0.01.
According to an expert for the automotive industry, 68% of Americans know how to drive a manual transmission vehicle. Suppose 220 Americans are sampled. (Give results accurate to at least 4 decimal places.) a. Of the 220 people sampled, 160 respond that they know how to drive a manual transmission vehicle. What is the sample statistic p? p = b. Under the assumption that the industry expert's claim that 68% of Americans know how to drive a manual transmission vehicle is valid, what is the probability that the survey in part (a) would result in a p that is at least as high as the one found? c. Under the assumption that the industry expert's claim that 68% of Americans know how to drive a manual transmission vehicle is valid, what is the probability that the survey in part (a) would result in a p that is between 66% and 71%?
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According to a sociologist's research on U.S. residents' habits regarding religious faith, 38% of U.S. residents attend a religious service (any denomination) at least once per month. Suppose 310 U.S. residents are sampled. (Give results accurate to at least 4 decimal places.) a. Of the 310 people sampled, 132 respond that they attend a religious service at least once per month. What is the sample statistic p? p= 0.4258 b. Under the assumption that the sociologist's claim that 38% of U.S. residents attend a religious service at least once per month is valid, what is the probability that the survey in part (a) would result in a p that is at least as high as the one found? c. Under the assumption that the sociologist's claim that 38% of U.S. residents attend a religious service at least once per month is valid, what is the probability that the survey in part (a) would result in a p that is between 37% and 40%?
The Board of Visitors hypothesize that self-esteem is increased by the time spent in college. After completing their junior year, a random sample of students was selected and given the Self-Esteem Adult Survey (SEAS). After completing their senior year they were again tested. What can be conclude with an a of 0.01? junior senior 5.9 2.1 7.2 7.5 7.4 6.9 6.8 6.3 8.5 5.5 6.2 6.4 7.3 4.6 5.2 5.2 a) What is the appropriate test statistic? Related-Samples t-test b) Condition 1: junior Condition 2: senior c) Input the appropriate value(s) to make a decision about Ho. p-value = ; Decision: --Select--- d) Using the SPSS results, compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. ; Magnitude: ; Magnitude: ---Select--- d = --Select--- 2 = e) Make an interpretation based on the results. O Students showed significantly less self-esteem in their senior year as opposed to their junior year. O Students showed significantly more…
a survey is conducted to compare the proportions of men and women whoaccess their bank statements online. Denoting the population propotions by Pm and Pw, a two-proportion z-test is carried out to test Ho: pm = pw against Ha: pm > pw. The values of the test statistic is found to be z = 0.784, and the p-value for the test is found to be 0.216. Which of the following is the correct interpretation of the p-value? a) given that ha is true, the probability of getting a value of z at least as large as 0.784 is 0.216. b) given the results of the survey, the probability that Pm > Pw is 0.216. c) given the results of the survey, the probability that Pm = Pw is 0.216. d) none of the above
A poll in 2017 reported that 680 out of 1026 adults in a certain country believe that marijuana should be legalized. When this poll about the same subject was first conducted in 1969, only 12% of the adults of the country supported legalization. Assume the conditions for using the CLT are met. Complete parts (a) through (d) below. a. Find and interpret a 99% confidence interval for the proportion of adults in the country in 2017 that believe marijuana should be legalized. The 99% confidence interval for the proportion of adults in the country in 2017 that believe marijuana should be legalized is (. ). (Round to three decimal places as needed.) Interpret this interval. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals rounded to three decimal places as needed.) O A. We are % confident that the population proportion of adults who believe marijuana should be legalized is between and O B. There is a % chance that the population…

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