**Title: Understanding Sampling and Probability with Manual Transmission Knowledge****Introduction:**According to an expert in the automotive industry, 68% of Americans are knowledgeable about driving a manual transmission vehicle. This exercise explores statistical sampling and probability by considering a sample of 220 Americans. The results should be calculated to at least four decimal places.**Question A: Calculating the Sample Statistic**- In the given sample of 220 people, 160 individuals report that they know how to drive a manual transmission vehicle.- **Task:** Determine the sample statistic \(\hat{p}\).\[\hat{p} = \frac{\text{Number of people who know how to drive manual}}{\text{Total number of people sampled}} = \frac{160}{220}\]**Question B: Probability of Observing a High Sample Proportion**- Assuming the expert's claim that 68% of Americans can drive a manual transmission vehicle is true, what is the probability that the sample statistic \(\hat{p}\) from part (a) would be at least as high as the calculated value?**Question C: Probability of Observing a Moderate Range of Sample Proportions**- Again, assuming the expert's 68% claim holds, calculate the probability that the sample statistic \(\hat{p}\) from part (a) falls between 66% and 71%.**Conclusion:**This exercise helps in understanding how real-world data is gathered and analyzed to form conclusions about broader populations. Through calculating and interpreting sample statistics and probabilities, we can gain insights into the validity of expert claims.

Answered: According to an expert for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a city with three high schools, all the ninth graders took a Standardized Test, with these results: Number of ninth graders High School Mean score on test Glenwood Central City Lincoln High 81 92 72 273 333 159 The city's PR manager, who never took statistics, claimed the mean score of all ninth graders in the city was 81.7. Of course, that is incorrect. What is the mean score for all ninth graders in the city? Round to one decimal place. mean of all ninth grader's scores =
In a city with three high schools, all the ninth graders took a Standardized Test, with these results: High School Mean score on test Number of ninth graders Glenwood 80 289 Central City 93 342 Lincoln High The city's PR manager, who never took statistics, claimed the mean score of all ninth graders in the city was 80. Of course, that is incorrect. What is the mean score for all ninth graders in the city? Round to one decimal place. 67 170 mean of all ninth grader's scores =
The U.S. National Center for Health Statistics complies birth statistics and publishes the results in vital statistics of the United States. The Center has historically believed that the mean of all newborns in the U.S. has been no less than 6.95 pounds. A sample of babies is selected so that the center can revise its belief. The following birth weights, in pounds are recorded: 7.4, 6.0, 8.6, 4.5, 2.0, 7.9, 4.0, 2.6, 5.9, 7.3, 7.3, 7.0, 6.3, 8.1, 7.1, 7.3, 6.6, 5.2, 9.8, 8.0, 10.9, 6.5, 3.8, 5.0, 8.0 a). At 5% level of significance, do these data provide sufficient evidence to refute the Center’s belief? Your conclusion must be in terms of the P-Value as well as setting up a Rejection Region. You must show all necessary work. b). Which statistical distribution should be applied in this situation and why? Explain carefully.
The problem is It is widely believed that 19% of all students live in campus housing. You suspect that claim is not accurate. You take a sample of 150 students from the population and find that 39 of those students live in campus housing. The part I am having trouble with is: Assuming the null is true, how many standard errors is the sample proportion away from the null? I need help remembering how to find the standard error. I know that the answer is 2.19.
At their inauguration, the ages of the first six (out of a current number of 45) presidents of a certain country were 60, 51, 50, 58, 51, and 55 . Complete parts a and b below. a. Find the mean age at inauguration of the first six presidents. The mean is 54.254.2. (Round to the nearest tenth as needed.) The mean of the most recent six presidents was 51.6. Did the first six presidents tend to be a bit older or a bit younger than the most recent six presidents? older Your answer is correct. younger b. Find the standard deviation of the ages at inauguration of the first six presidents. The standard deviation is nothing. (Round to the nearest tenth as needed.)

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