A researcher wishes to determine whether there is a difference in the average age ofmiddle school, high school, and college teachers. Teachers are randomly selected.Their ages are recorded below. Find the test statistic F to test the hypothesis thatthere is no difference in the average age of each group. Use a = 0.01.Middle School Teachers High School Teachers College Teachers232827375225OA) 4.312B) 2.913C) 2.517OD) 3.189383641474231364539614535

Answered: Image /qna-images/answer/18bce32e-b7d7-4e88-aebd-90a001d6eca3.jpg

Answered: A researcher wishes to determine…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher randomly purchases several different kits of a popular building toy. The following table shows the number of pieces in each kit in the sample. Find the mean of the data. Round your answer to the nearest hundredth, if necessary. Building Toy Pieces 152 37 257 342 342 37 96 288 257 101 162 200 Copy Data
A statistic is a number that... describes a characteristic of a population of scores. describes a characteristic of a sample of scores. is never used to estimate or make a decision about a parameter. summarizes all the individuals a researcher is interested in.
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
The table below shows the scores of a group of students on a 10-point quiz. Test Score Frequency 3 1 4 1 7 4 8 4 9. 10 2 The mean score on this test is: The median score on this test is: Check Answer
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
A J.D. Power and Associates vehicle quality survey asked new owners a variety of questions about their recently purchased automobile. One question asked for the owner's rating of the vehicle using categorical responses of average, outstanding, and exceptional. Another question asked for the owner's education level with the categorical responses some high school, high school graduate, some college, and college graduate. Assume the sample data below are for 500 owners who had recently purchased an automobile. Education Quality Rating Some HS HS Grad Some College College Grad Average 30 30 20 60 Outstanding 50 50 50 90 Exceptional 20 20 30 50 a. Use a 0.05 level of significance and a test of independence to determine if a new owner's vehicle quality rating is independent of the owner's education. Compute the value of the x test statistic (to 2 decimals). Use Table 3 of Appendix B to find the p-value. The p-value is - Select your answer - What is your conclusion? - Select your answer - v…
The table below shows the scores of a group of students on a 10-point quiz. Test Score Frequency 3 4 4 2 5 2 6 3 7 1 8 4 9 2 10 1 The mean score on this test is: IncorrectThe median score on this test is: Show your work
The table below shows the scores of a group of students on a 10-point quiz. Frequency Test Score 3 4 5 6 7 8 9 10 2 3 0 3 3 3 4 4 The mean score on this test is: The median score on this test is:
A survey was given to 18 students. One question asked about the one-way distance the student had to travel to attend college. The results, in miles, are shown in the following table. Use the median procedure for finding quartiles to find the first, second, and third quartiles for the data. Distance Traveled to Attend College 34 42 16 18 50 74 2 28 32 32 14 66 72 32 86 24 18 40 Q1=Q2=Q3=
Here are the reading scores (out of 60) of 20 randomly selected kindergarten kids in a district 34, 26, 46, 46, 43, 42, 45, 39, 43, 32, 15, 36, 29, 39, 41, 27, 38, 58, 31, 35 Find the 5-number summary for the data set. Min: Q1: Median: Q3: Find the IQR of the data set. IQR: Find Q3+1.5(IQR). Q3+1.5(IQR) = Max: Are there any high outliers, that is, are there any numbers in the data set higher than Q3+1.5(IQR)? Select an answer Find Q₁-1.5(IQR). Q₁-1.5(IQR) Are there any low outliers, that is, are there any numbers in the data set higher than Q₁— 1.5(IQR)? Select an answer No, there are no low outliers 15 is a low outlier =

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