An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both a=0.05 and a=0.10 levels of significance and the critical value method with the table. Part 1 of 5 State the appropriate null and alternate hypotheses. Ho: P = .11 H:p> .11 This hypothesis test is a right-tailed V test. Part 2 of 5 Find the critical values. Round the answer to three decimal places. For a-0.05 , the critical value is 1.645 For a= 0.10, the critical value is 1.282 Part 3 of 5 Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places. z= 2.39 Part: 3/5 Part 4 of 5 Determine whether to reject H. At the a=0.05 level, (Choose one) ▼ the null hypothesis H. At the a 0.10 level, (Choose one) 7 the null hypothesisH

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**Confidence in Banks**

A news poll conducted in 2012 asked a random sample of 1217 adults in the United States how much confidence they had in banks and other financial institutions. A total of 160 adults said that they had a great deal of confidence. An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both \(\alpha = 0.05\) and \(\alpha = 0.10\) levels of significance and the critical value method with the table.

### Part 1 of 5

**State the appropriate null and alternate hypotheses.**

\[H_0: p = 0.11\]

\[H_1: p > 0.11\]

This hypothesis test is a **right-tailed** test.

### Part 2 of 5

**Find the critical values. Round the answer to three decimal places.**

- For \(\alpha = 0.05\), the critical value is \[1.645\].
- For \(\alpha = 0.10\), the critical value is \[1.282\].

### Part 3 of 5

**Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places.**

\[z = 2.39\]

### Part 4 of 5

**Determine whether to reject \(H_0\).**

- At the \(\alpha = 0.05\) level, \[Choose one: (Reject/Fail to reject)\] the null hypothesis \(H_0\).
- At the \(\alpha = 0.10\) level, \[Choose one: (Reject/Fail to reject)\] the null hypothesis \(H_0\).

### Part 5 of 5

Explanation of the decision based on the significance levels and the critical values. 

(Note: The values in brackets are placeholders and should be replaced with the appropriate decision, whether to reject or fail to reject the null hypothesis.)
Transcribed Image Text:**Confidence in Banks** A news poll conducted in 2012 asked a random sample of 1217 adults in the United States how much confidence they had in banks and other financial institutions. A total of 160 adults said that they had a great deal of confidence. An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both \(\alpha = 0.05\) and \(\alpha = 0.10\) levels of significance and the critical value method with the table. ### Part 1 of 5 **State the appropriate null and alternate hypotheses.** \[H_0: p = 0.11\] \[H_1: p > 0.11\] This hypothesis test is a **right-tailed** test. ### Part 2 of 5 **Find the critical values. Round the answer to three decimal places.** - For \(\alpha = 0.05\), the critical value is \[1.645\]. - For \(\alpha = 0.10\), the critical value is \[1.282\]. ### Part 3 of 5 **Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places.** \[z = 2.39\] ### Part 4 of 5 **Determine whether to reject \(H_0\).** - At the \(\alpha = 0.05\) level, \[Choose one: (Reject/Fail to reject)\] the null hypothesis \(H_0\). - At the \(\alpha = 0.10\) level, \[Choose one: (Reject/Fail to reject)\] the null hypothesis \(H_0\). ### Part 5 of 5 Explanation of the decision based on the significance levels and the critical values. (Note: The values in brackets are placeholders and should be replaced with the appropriate decision, whether to reject or fail to reject the null hypothesis.)
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