A well-known brokerage firm executive claimed that 80% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 200 people, 83% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 80% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:u < 0.8 Ho:p = 0.8 Ho:u = 0.8 Ho:p > 0.8 Ho:p < 0.8 Ho:u > 0.8 H1:u > 0.8 H1:p 0.8 H1:u 0.8 H1:p < 0.8 H1:p> 0.8 H:p<0.8 %3D The test is: left-tailed right-tailed two-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

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Question TU
A well-known brokerage firm executive claimed that 80% of investors are currently confident of
meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week
period, found that in a sample of 200 people, 83% of them said they are confident of meeting their
goals.
Test the claim that the proportion of people who are confident is larger than 80% at the 0.01
significance level.
The null and alternative hypothesis would be:
Ho:u < 0.8 Ho:p = 0.8 Ho:u = 0.8 Ho:p > 0.8 Ho:p < 0.8 Ho:p > 0.8
H1:p > 0.8 H:p 0.8 H1: µ # 0.8 H1:p < 0.8 H1:p > 0.8 H1:p <0.8
The test is:
left-tailed right-tailed two-tailed
The test statistic is:
(to 3 decimals)
The p-value is:
(to 4 decimals)
Based on this we:
O Reject the null hypothesis
O Fail to reject the null hypothesis
> Next Question
M
Transcribed Image Text:Question TU A well-known brokerage firm executive claimed that 80% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 200 people, 83% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 80% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:u < 0.8 Ho:p = 0.8 Ho:u = 0.8 Ho:p > 0.8 Ho:p < 0.8 Ho:p > 0.8 H1:p > 0.8 H:p 0.8 H1: µ # 0.8 H1:p < 0.8 H1:p > 0.8 H1:p <0.8 The test is: left-tailed right-tailed two-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis > Next Question M
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