An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engineanalyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks inthe experiment. The data obtained follow.CarCompactIntermediateFull-sized#Ho: MComputerized * μElectronicHa: ComputerizedMElectronicHo: "Computerized MElectronic#Ha: μComputerized ‡ µElectronicComputerized52Use a = 0.05 to test for any significant differences.State the null and alternative hypotheses.=53=63# μFull-sizedHo: MCompact MIntermediate#Ha: Compact = MIntermediate μFull-sizedAnalyzerElectronic4145Ho: MComputerized = μElectronic Compact MIntermediateNot all the population means are equal.Ha:Ho: MCompact = MIntermediate Full-sizedHa: MCompact ##MIntermediate Full-sized46Full-sized Find the value of the test statistic. (Round your answer to two decimal places.)0.0859Find the p-value. (Round your answer to three decimal places.)p-value = = 0.020XState your conclusion.Reject Ho. There is not sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.Do not reject Ho. There is not sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.Do not reject Ho. There is sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.Reject Ho. There is sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.

Answered: An automobile dealer conducted a test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Ost watched Ani... Question 2 Y Part 1 of 4 A doctor in Cleveland wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 9% level of significance to test whether the average life span of heart disease patients in Cleveland differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 7.4, 7.8, 7.7, 7.5, 8, 8.2, 7.8, 8.6, 8, 7.8, 8.3, 8.3, 8, 7.6, 8.2, 7.9, 7.3, 8, 8.6, 7.3, 8.3, 8, 7.8, 8, 7.8, 8.1, 8.1, 8, 7.6, 7.6, 7.7, 7.4, 7.7, 7.8, 7.8 Life Span of Patients Treated at Hospital 2: 7.9, 7.9, 8.2, 8, 8.1, 8.5, 8.3, 8.4, 8, 8.2, 7.7, 8, 8, 7.8, 7.9, 8.1, 8.1, 7.8, 7.9, 8, 8.5, 8.3, 8.2, 8.3, 7.8, 7.9 Life Span of Patients Treated at Hospital 3: 8.2, 8.1, 7.4, 8.7, 8.6, 8.2, 7.9, 8.1, 8.1, 8.3, 8.3, 8, 7.6, 8, 7.4, 8.6, 8.2, 8.2, 7.9, 7.7, 8.1, 7.9, 8, 8.3 Life Span of…
Part 1 of 4 A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital 4:…
A researcher hypothesizes that different colors of cars result in different average speeds. To test this claim, she took a random sample of 20 people who own 4 different colors of colors of cars (n = 20, N = 80, G = 4), and she then tracks their average speed on the highway for a week of driving. The following ANOVA table has some of her results. Please help her answer her research questions by completing the following ANOVA table below and answering the follow-up questions. Be sure to label your answers with the appropriate letter and show all your work! Source Sums of Squares df Mean Square F Effect (between) Error (within) 100.90 ------ Total 170.10 ------- ------ a) What is the Sums of Squares (SS) between (effect)? b) What are the Mean Square (MS) between (effect) and the MS within (error)? c) What are the degrees of freedom (df) between, the df within, and the df total? d) What is the overall F-statistic? e) Based on the…
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The data on the number of chocolate chips per bag for 42 bags of Chips Ahoy! cookies were obtained by the students in an introductory statistics class at the United States Air Force Academy in response to the Chips Ahoy! 1,000 Chips Challenge sponsored by Nabisco, the makers of Chips Ahoy! Use the data collected by the students to answer the following questions and to conduct the analyses required in each part. They found æ = 1261.6 and s = 117.6 a. Determine a 95% confidence interval for the mean number of chips per bag for all bags of Chips Ahoyl cookies. b. Interpret your result in words. C. Can you conclude that the average bag of Chips Ahoy! Cookies contain at least 1000 chocolate chips? O yes Ono Ads in 4 d. Explain why or why not. + SAVE MacBook Pro FR.IEN DS DII DD F12 F11 F8 F9 F10 F7 F5 ) 7 8 9. %3D dela { } Y U P [
An observational study of teams fishing for the red spiny lobster in a certain body of water was conducted and the results published in a science magazine. One of the variables of interest was the average distance separating traps - called "trap spacing" - deployed by the same team of fishermen. Trap spacing measurements (in meters) for a sample of seven teams of fishermen are shown in the accompanying table. Of interest is the mean trap spacing for the population of red spiny lobster fishermen fishing in this body of water. Complete parts a through f below. E Click the icon to view the trap spacing data. Trap Spacing Data a. Identify the target parameter for this study. The target parameter for this study is 93 101 107 95 81 68 84 b. Compute a point estimate of the target parameter. (Round to two decimal places as needed.) Print Done c. What is the problem with using the normal (z) statistic to finda confidence interval for the target parameter? O A. The point estimate is too large to…

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