An article suggests that substrate concentration (mg/cm³) of influent to a reactor is normally distributed with μ = 0.50 and σ = 0.09. (Round your answers to four decimal places.) I USE SALT (a) What is the probability that the concentration exceeds 0.70? (b) What is the probability that the concentration is at most 0.40? (c) How would you characterize the largest 5% of all concentration values? The largest 5% of all concentration values are above mg/cm³. You may need to use the appropriate table in the Appendix of Tables to answer this question.
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- The acceptable level for insect filth in a certain food item is 5 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 50 ten-gram portions of the food item is obtained and results in a sample mean of x = 5.3 insect fragments per ten-gram portion. Complete parts (a) through (c) below. o: = 0.316 (Round to three decimal places as needed.) (c) What is the probability a simple random sample of 50 ten-gram portions of the food item results in a mean of at least 5.3 insect fragments? P(x 2 5.3) = ||| (Round to four decimal places as needed.)The acceptable level for insect filth in a certain food item is 5 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 50 ten-gram portions of the food item is obtained and results in a sample mean of x = 5.3 insect fragments per ten-gram portion. Complete parts (a) through (c) below. H = 5 (Round to three decimal places as needed.). o: = 0.316 (Round to three decimal places as needed.) (c) What is the probability a simple random sample of 50 ten-gram portions of the food item results in a mean of at least 5.3 insect fragments? P(x2 5.3) = (Round to four decimal places as needed.)(a) A certain type of hummingbird is known to have an average weight of 4.55 grams. A researcher wonders if hummingbirds (of this same type) living in the Grand Canyon differ in weight from the population as a whole. The researcher finds a sample of 30 such hummingbirds from the Grand Canyon and calculates their average weight to be 3.75 grams. Ο Α. H : μ = 4.55, Ο B. H : μ 3.75 D. Ho = 4.55, H₁ 4.55 OE. Ho = 4.55, H 115 OB. Ho = 118.2, Ha 118.2 Ο C. H : μ = 118.2, H@ :μ 115 OE. Ho = 115, H₁115 F. Ho = 115, H₂ 69 Ο C. H : μ = 71, H@ :μ 69, Ha : μ 69
- (still referring to the table) For a one-unit increase in X1 for observations with X2=0, what is the expected change in Y? What about for observations with X2=1? a. -0.778 b. 0.344 c. 0.055 d. -0.723Brake wear: For a sample of 9 automobiles, the mileage (in 1000 s of miles) at which the original front brake pads were worn to 11% of their original thickness was measured, as was the mileage at which the original rear brake pads were worn to 11% of their original thickness. The results were as follows: Car Rear Front 1 41.2 32.7 2 35.9 27.6 46.8 35.5 46.3 38.2 38.6 29.2 51.9 43.9 51.3 41.2 46.7 37.6 46.1 38.0 3 4 5 6 7 8 9 Send data to Excel Part: 0 / 2 Part 1 of 2 (a) Construct a 95% confidence interval for the difference in mean lifetime between the front and rear brake pads. Let d represent the mileage of the rear pads minus the mileage of the front ones. Round the answers to two decimal places. A 95% confidence interval for the mean difference in lifetime between front and rear brake pads is kua < Par Part: 1 / 2 of 2 X (b) An automotive engineer claims that the mean lifetime for rear brake pads is more than 10,000 miles more than the mean lifetime for front brake pads. Does the…A random sample from a normal population has:n = 8, X-bar = 16, and s = 3. Find the 95% PI for asingle new value from the population.
- “Normal” BMI is up to 25 kg/m2. A laboratory study is being conducted to determine energy expenditure for those who are overweight and/or obese. The researchers have enrolled only subjects with BMI above 25.0 and have quantified obesity as “units above normal”. For example, a subject with BMI of 32.3 is recorded as 7.3 (i.e. 32.3 – 25.0 = 7.3). Using this scheme, the mean obesity was found to be 8.7 kg/m2and the standard deviation was 6.4 kg/m2. If we convert the obesity measure used in this study back into conventional BMI (i.e., add 25.0 units to each measurement), what will the standard deviation be? Group of answer choices The standard deviation will be larger on the BMI scale because 25.0 units will be added back. The standard deviation will be the same 6.4 kg/m2 There is not enough information to determine this The standard deviation will be smaller on the BMI scale because, as a percentage of the whole scale, the difference between each subject and the mean will be…1. Can balloons hold more air or more water before bursting? A student purchased a large bag of 12-inch balloons. He randomly selected 10 balloons from the bag and then randomly assigned half of them to be filled with air until bursting and the other half to be filled with water until bursting. He used devices to measure the amount of air and water was dispensed until the balloons burst. Here's the data: Air (ft') Water (ft) 0.52 0.44 0.58 0.41 0.50 0.55 0.46 0.61 0.38 0.45 Does the data give convincing evidence air filled balloons can attain a greater volume than water filled balloons?The American Mineralogist (Oct. 2009) published a study of the evolution of uranium minerals in the Earth's crust. Researchers estimate that the trace amount of uraniun distribution ranging between 1 and 3 parts per million. Complete parts a through c. a. Find E(x) and interpret its value. Select the correct answer below and fill in the answer box to complete your choice. (Simplify your answer.) O A. E(X)= .This value gives the minimum parts per million of uranium for the collection of all reservoirs on the Earth. O B. E(X)= This value gives the maximum parts per million of uranium for the collection of all reservoirs on the Earth. O C. E(x) = 2 . This value gives the mean parts per million of uranium for the collection of all reservoirs on the Earth. O D. E(X)= . This value gives the mean parts per million of uranium in each reservoir on the Earth. b. Compute P(2If X = 85, Y = 54, and Y' = 62, what is the residual score? a. -8 b. 23 c. 8 d. 31Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=111μ=111 and σ=15σ=15. (a) What proportion of children aged 13 to 15 years old have scores on this test above 93 ? (NOTE: Please enter your answer in decimal form. For example, 45.23% should be entered as 0.4523.) (b) Enter the score which marks the lowest 30 percent of the distribution. (c) Enter the score which marks the highest 10 percent of the distribution.