An article gave a scatter plot, along with the least squares line, of x = rainfall volume (m3) and y = runoff volume (m3) for a particular location. The simple linear regression model provides a very good fit to data on rainfall and runoff volume (n = 15) given below. The equation of the least squares line is y = −1.495 + 0.83011x, r2 = 0.978, and s = 4.96. x 5 12 14 17 23 30 40 47 55 67 72 81 96 112 127 y 4 10 13 15 15 24 26 45 38 46 54 69 81 99 101 (a) Use the fact that sy hat = 1.36 when rainfall volume is 40 m3 to predict runoff in a way that conveys information about reliability and precision. (Calculate a 95% PI. Round your answers to two decimal places.) , m3 Does the resulting interval suggest that precise information about the value of runoff for this future observation is available? Explain your reasoning. Yes, precise information is available because the resulting interval is very wide. Yes, precise information is available because the resulting interval is very narrow. No, precise information is not available because the resulting interval is very wide. No, precise information is not available because the resulting interval is very narrow. (b) Calculate a 95% PI for runoff when rainfall is 50. (Round your answers to two decimal places.) , m3 What can be said about the simultaneous prediction level for the two intervals you have calculated? The simultaneous prediction level for the intervals is at least %. You may need to use the appropriate table in the Appendix of Tables to answer this question.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An article gave a scatter plot, along with the least squares line, of x = rainfall volume (m3) and y = runoff volume (m3) for a particular location. The simple linear regression model provides a very good fit to data on rainfall and runoff volume (n = 15) given below. The equation of the least squares line is y = −1.495 + 0.83011x, r2 = 0.978, and s = 4.96. x 5 12 14 17 23 30 40 47 55 67 72 81 96 112 127 y 4 10 13 15 15 24 26 45 38 46 54 69 81 99 101 (a) Use the fact that sy hat = 1.36 when rainfall volume is 40 m3 to predict runoff in a way that conveys information about reliability and precision. (Calculate a 95% PI. Round your answers to two decimal places.) , m3 Does the resulting interval suggest that precise information about the value of runoff for this future observation is available? Explain your reasoning. Yes, precise information is available because the resulting interval is very wide. Yes, precise information is available because the resulting interval is very narrow. No, precise information is not available because the resulting interval is very wide. No, precise information is not available because the resulting interval is very narrow. (b) Calculate a 95% PI for runoff when rainfall is 50. (Round your answers to two decimal places.) , m3 What can be said about the simultaneous prediction level for the two intervals you have calculated? The simultaneous prediction level for the intervals is at least %. You may need to use the appropriate table in the Appendix of Tables to answer this question.

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