An article considered the use of a uniform distribution with A = 0.20 and B = 4.25 for the diameter X of a certain type of weld (mm). (a) Determine the pdf of X. (Round your answers to three decimal places.) X f(x) = 0.20

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Chapter1: Combinatorial Analysis
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An article considered the use of a uniform distribution with A = 0.20 and B = 4.25 for the diameter X of a certain type of weld (mm).
(a) Determine the pdf of X. (Round your answers to three decimal places.)
0.20 < x < 4.25
otherwise
f(x) =
0
Graph the pdf of X.
f(x)
0.5
0.4
0.3
0.2
0.1
f(x)
0.5
0.4
0.3
0.2
0.1
1
1
X
✔
2
2
3
3
4
4
5
5
f(x)
0.5
0.4
0.3
0.2
0.1
f(x)
0.5
0.4
0.3
0.2
0.1
1
1
2
2
(b) What is the probability that diameter exceeds 2 mm? (Round your answer to three decimal places.)
3
3
4
4
5
X
(c) What is the probability that diameter is within 2 mm of the mean diameter? (Round your answer to three decimal places.)
x
(d) For any value a satisfying 0.20 < a <a + 4 < 4.25, what is P(a < x <a +4)? (Round your answer to three decimal places.)
Transcribed Image Text:An article considered the use of a uniform distribution with A = 0.20 and B = 4.25 for the diameter X of a certain type of weld (mm). (a) Determine the pdf of X. (Round your answers to three decimal places.) 0.20 < x < 4.25 otherwise f(x) = 0 Graph the pdf of X. f(x) 0.5 0.4 0.3 0.2 0.1 f(x) 0.5 0.4 0.3 0.2 0.1 1 1 X ✔ 2 2 3 3 4 4 5 5 f(x) 0.5 0.4 0.3 0.2 0.1 f(x) 0.5 0.4 0.3 0.2 0.1 1 1 2 2 (b) What is the probability that diameter exceeds 2 mm? (Round your answer to three decimal places.) 3 3 4 4 5 X (c) What is the probability that diameter is within 2 mm of the mean diameter? (Round your answer to three decimal places.) x (d) For any value a satisfying 0.20 < a <a + 4 < 4.25, what is P(a < x <a +4)? (Round your answer to three decimal places.)
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