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Let "X" denote the shaft clearance (in mm) which is the difference between the radius of the hole (where the shaft is inserted) and the radius of the shaft. For the pdf shown below, what proportion of the components are acceptable if clearances larger than 0.8 mm are scrapped? S1.25(1 – x*) 0 < x < 1 f (x) = otherwise 0.174 0.826 none of these 0.082 0.918

Let "X" denote the shaft clearance (in mm) which is the difference between the radius of the hole (where the shaft is inserted) and the radius of the shaft. For the pdf shown below, what proportion of the components are acceptable if clearances larger than 0.8 mm are scrapped? S1.25(1 – x*) 0 < x < 1 f (x) = otherwise 0.174 0.826 none of these 0.082 0.918

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Let "X" denote the shaft clearance (in mm) which is the difference between the radius of the hole (where the shaft is inserted) and the radius of the shaft. For the pdf shown below, what proportion of the components are acceptable if clearances larger than 0.8 mm are scrapped? S1.25(1 – x*) 0 < x < 1 f(x) = otherwise 0.174 0.826 none of these 0.082 0.918
Transcribed Image Text:Let "X" denote the shaft clearance (in mm) which is the difference between the radius of the hole (where the shaft is inserted) and the radius of the shaft. For the pdf shown below, what proportion of the components are acceptable if clearances larger than 0.8 mm are scrapped? S1.25(1 – x*) 0 < x < 1 f(x) = otherwise 0.174 0.826 none of these 0.082 0.918
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