An aqueous solution is 6.00% by mass ethanol, CH,CH,OH, and has a density of 0.988 g/mL. The molarity of ethanol in the solution is М.

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**Title: Calculating Molarity of Ethanol Solution**

**Problem Statement:**
An aqueous solution contains 6.00% by mass ethanol, \( CH_3CH_2OH \), and has a density of 0.988 g/mL. The task is to determine the molarity of ethanol in the solution.

**Steps to Solve:**
1. **Identify the percentage by mass**: The solution is 6.00% ethanol by mass. This means 6.00 grams of ethanol are present in 100 grams of solution.
  
2. **Determine the density**: The solution has a density of 0.988 g/mL. Using this, convert the total mass of the solution to volume.

3. **Convert mass to volume**:
   \[ \text{Volume of solution} = \frac{\text{Mass of solution}}{\text{Density of solution}} = \frac{100\, \text{g}}{0.988\, \text{g/mL}} \]

4. **Calculate the moles of ethanol**:
   The molar mass of ethanol (\( CH_3CH_2OH \)) is 46.07 g/mol.
   \[ \text{Moles of ethanol} = \frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}} = \frac{6\, \text{g}}{46.07\, \text{g/mol}} \]

5. **Calculate molarity**:
   \[ \text{Molarity} = \frac{\text{Moles of ethanol}}{\text{Volume of solution in liters}} \]

6. **Submit your calculated answer** in the provided input box and click on "Submit Answer".

**Buttons/Options:**
- **Submit Answer**: Click this button after entering your calculated molarity to see if it's correct.
- **Try Another Version**: If your answer is not correct, you can click this button to attempt another version of the problem.
  
You have 7 attempts remaining to solve this problem.

Use the [References] link to access important values if needed for the question.
Transcribed Image Text:**Title: Calculating Molarity of Ethanol Solution** **Problem Statement:** An aqueous solution contains 6.00% by mass ethanol, \( CH_3CH_2OH \), and has a density of 0.988 g/mL. The task is to determine the molarity of ethanol in the solution. **Steps to Solve:** 1. **Identify the percentage by mass**: The solution is 6.00% ethanol by mass. This means 6.00 grams of ethanol are present in 100 grams of solution. 2. **Determine the density**: The solution has a density of 0.988 g/mL. Using this, convert the total mass of the solution to volume. 3. **Convert mass to volume**: \[ \text{Volume of solution} = \frac{\text{Mass of solution}}{\text{Density of solution}} = \frac{100\, \text{g}}{0.988\, \text{g/mL}} \] 4. **Calculate the moles of ethanol**: The molar mass of ethanol (\( CH_3CH_2OH \)) is 46.07 g/mol. \[ \text{Moles of ethanol} = \frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}} = \frac{6\, \text{g}}{46.07\, \text{g/mol}} \] 5. **Calculate molarity**: \[ \text{Molarity} = \frac{\text{Moles of ethanol}}{\text{Volume of solution in liters}} \] 6. **Submit your calculated answer** in the provided input box and click on "Submit Answer". **Buttons/Options:** - **Submit Answer**: Click this button after entering your calculated molarity to see if it's correct. - **Try Another Version**: If your answer is not correct, you can click this button to attempt another version of the problem. You have 7 attempts remaining to solve this problem. Use the [References] link to access important values if needed for the question.
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