An analytical chemist weighs out 0.115 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1500M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 8.5 mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits. mol

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**Titration and Calculating Molar Mass of an Unknown Acid**

An analytical chemist weighs out 0.115 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1500 M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 8.5 mL of NaOH solution.

Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits.

*Answer Box:*  
The text box where the answer should be filled in is labeled with units \(\frac{\text{g}}{\text{mol}}\).

*Input features:*  
There is also an input control with the following buttons:
- \( \times 10 \) for scientific notation
- An "X" button, likely for clearing the input
- A reset or undo button
- A question mark possibly for help or hints
Transcribed Image Text:**Titration and Calculating Molar Mass of an Unknown Acid** An analytical chemist weighs out 0.115 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1500 M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 8.5 mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits. *Answer Box:* The text box where the answer should be filled in is labeled with units \(\frac{\text{g}}{\text{mol}}\). *Input features:* There is also an input control with the following buttons: - \( \times 10 \) for scientific notation - An "X" button, likely for clearing the input - A reset or undo button - A question mark possibly for help or hints
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