An analytical chemist is titrating 131.8 mL of a 0.7000M solution of propylamine (C3H-NH₂) with a 0.7800M solution of HNO3. The p K₂ of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 126.1 mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places.
An analytical chemist is titrating 131.8 mL of a 0.7000M solution of propylamine (C3H-NH₂) with a 0.7800M solution of HNO3. The p K₂ of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 126.1 mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![An analytical chemist is titrating 131.8 mL of a 0.7000 M solution of propylamine (C₃H₇NH₂) with a 0.7800 M solution of HNO₃. The pK_b of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 126.1 mL of the HNO₃ solution to it.
*Note for advanced students:* you may assume the final volume equals the initial volume of the solution plus the volume of HNO₃ solution added.
Round your answer to 2 decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F321870cf-5f02-4a7a-9bd1-b1bcd10d94da%2F14e183b5-f018-44cb-9181-c425b918fff1%2Fl4pcg5_processed.png&w=3840&q=75)
Transcribed Image Text:An analytical chemist is titrating 131.8 mL of a 0.7000 M solution of propylamine (C₃H₇NH₂) with a 0.7800 M solution of HNO₃. The pK_b of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 126.1 mL of the HNO₃ solution to it.
*Note for advanced students:* you may assume the final volume equals the initial volume of the solution plus the volume of HNO₃ solution added.
Round your answer to 2 decimal places.
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