An AM signal of 50 watt power is transmitted in a frequency range 100-103 kHz in a transmission channel. If the additive noise power spectral density (two- sided) in a transmission channel is lu watt/Hz. Find the signal-to-noise ratio in the transmission channel. Amp AM signal Solution: 10 S = 50 watt Noise 2067 103 2067 103 1 N = 2n 200n 103 | S,(w)dw 10-6dw = 6 x 10-3watt 200n 103 Or simply N = nB = 10-6 Watt * 2 * 3000 Hz = 6 x 10-3watt Hz 50 SNR = 8333.33 6x10-3 SNRAB = 10 log 8333.33 = 39.208 dB %3D Compute SNR for the previous example if PSD of noise is not white and given by 10-6 f watt/Hz. (what is the conclusion you obtained for this colored noise assumption as compared with white case? ). 103 kHz 100 kHz 100 kHz -103 kHz

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An AM signal of 50 watt power is transmitted in a frequency range 100-103
kHz in a transmission channel. If the additive noise power spectral density (two-
sided) in a transmission channel is lu watt/Hz. Find the signal-to-noise ratio in the
transmission channel.
Amp
AM signal
Solution:
10
S = 50 watt
Noise
20677 103
2
2067 103
N =
Sn(@)dw
10-6dw = 6 x 10-3watt
2n
2007n 103
200n 103
Or simply N = ŋB = 10-6 watt
* 2 * 3000 Hz = 6x 10-3watt
Hz
50
SNR =
N
= 8333.33
6x10-3
SNRAB = 10 log 8333.33 = 39.208 dB
%3D
Compute SNR for the previous example if PSD of noise is not white and given
by 10-6 f watt/Hz. (what is the conclusion you obtained for this colored noise
assumption as compared with white case? ).
103 kHz
100 kHz
-100 kHz
-103 kHz
Transcribed Image Text:An AM signal of 50 watt power is transmitted in a frequency range 100-103 kHz in a transmission channel. If the additive noise power spectral density (two- sided) in a transmission channel is lu watt/Hz. Find the signal-to-noise ratio in the transmission channel. Amp AM signal Solution: 10 S = 50 watt Noise 20677 103 2 2067 103 N = Sn(@)dw 10-6dw = 6 x 10-3watt 2n 2007n 103 200n 103 Or simply N = ŋB = 10-6 watt * 2 * 3000 Hz = 6x 10-3watt Hz 50 SNR = N = 8333.33 6x10-3 SNRAB = 10 log 8333.33 = 39.208 dB %3D Compute SNR for the previous example if PSD of noise is not white and given by 10-6 f watt/Hz. (what is the conclusion you obtained for this colored noise assumption as compared with white case? ). 103 kHz 100 kHz -100 kHz -103 kHz
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