An aluminum ring of radius r,=5 cm and resistance 3 X 10 is placed around one end of a -4 long air - core Bolenoid with 1000 turns per meter and figure. Assume the axial componient of the radius r2= 3 cm as shown in field by the solenoid is 'one- half as strong over the area of produced the end of the 'solenoid as at the center of the Sofenoid. Also assume the Sole noid produces negligible field outside its cross- sectional area. The current in the solenoid is inčreasing at a rate of 270 AIS. a) what is the inducad current in the ring? At the' center of the ring, what are b) the magnitude and c) the direction of the magnetic tield produced by the induced chrrent ring? in the R= 3X 10n A = nr?

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Can someone please help me figure out parts b and c in the attached problem? Thanks!
CHAPTER 23 (5)
An aluminum ring of radius r,=5 cm and resistance 3X 10 is placed
around one end of a
-4
long air - core Bolenoid with 1o00 turns per meter and
radius r2= 3 cm as shown in fiqure. Assume the axial component of the
field produced by the solenoid is 'one- half as strong over the area of
the end of the 'sclenoid as at the center of the sSolenoid. Also assume the
Sole noid produces negligible field outside its cross - sectional area. The current
in the solenoid is increasing at a rate of 270 AlS. a) what is the induced
current in the ring? At the' center of the ring, what are b) the magnitude
and c) the direction of the magnetic field produced by the induced drrent
in the ring!
1^I
R= 3X 10
A = nr?
r5 cm >.65m
HNG
N =
l000 TURNS /M
Soce
3 cm >,05m
AIIS INCREASING e 27o AIS
AŁ
A AREA IS Not CHANGING , MAG FIELD IS
I= 18|
148-A|
A AB
At
R
At
*ASSuming the axial component
AB =
b-늘 AB,
/2 strong over the area of solenoid as cen ter,
%3D
I Mo N AI
so, 1El= M, NTr?
(4T 10) 1000 I T L03),
SOL
270
At
M
I= 14.79x10"v |
3 x lo-2
1.59 A > l6A
4.79×10V
Transcribed Image Text:CHAPTER 23 (5) An aluminum ring of radius r,=5 cm and resistance 3X 10 is placed around one end of a -4 long air - core Bolenoid with 1o00 turns per meter and radius r2= 3 cm as shown in fiqure. Assume the axial component of the field produced by the solenoid is 'one- half as strong over the area of the end of the 'sclenoid as at the center of the sSolenoid. Also assume the Sole noid produces negligible field outside its cross - sectional area. The current in the solenoid is increasing at a rate of 270 AlS. a) what is the induced current in the ring? At the' center of the ring, what are b) the magnitude and c) the direction of the magnetic field produced by the induced drrent in the ring! 1^I R= 3X 10 A = nr? r5 cm >.65m HNG N = l000 TURNS /M Soce 3 cm >,05m AIIS INCREASING e 27o AIS AŁ A AREA IS Not CHANGING , MAG FIELD IS I= 18| 148-A| A AB At R At *ASSuming the axial component AB = b-늘 AB, /2 strong over the area of solenoid as cen ter, %3D I Mo N AI so, 1El= M, NTr? (4T 10) 1000 I T L03), SOL 270 At M I= 14.79x10"v | 3 x lo-2 1.59 A > l6A 4.79×10V
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