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(ii) An electron e- having kinetic energy 1.0 MeV has a head-on collision with a positron e* at rest. During the collision the two particles annihilate each other and are replaced by two photons of equal energy, each traveling at angles 0 with the electron's direction of motion. The reaction is e +e* → 2y Determine the energy E, momentum p and angle of emission 0 of each photon by using the mass energy momentum relation.

(ii) An electron e- having kinetic energy 1.0 MeV has a head-on collision with a positron e* at rest. During the collision the two particles annihilate each other and are replaced by two photons of equal energy, each traveling at angles 0 with the electron's direction of motion. The reaction is e +e* → 2y Determine the energy E, momentum p and angle of emission 0 of each photon by using the mass energy momentum relation.

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5. The free neutron is known to decay into a proton, an electron and an antineutrino (of zero rest mass) according to the following beta decay relation n → p+e¯ +v This beta decay products are measured to have a total kinetic energy of (0.781 ± 0.005) MeV. Show that this observation is consistent with the Einstein mass-energy relationship and determine the Am and the relevant energy E. (ii) An electron e- having kinetic energy 1.0 MeV has a head-on collision with a positron e* at rest. During the collision the two particles annihilate each other and are replaced by two photons of equal energy, each traveling at angles 0 with the electron's direction of motion. The reaction is e¯ +e* → 2y Determine the energy E , momentum p and angle of emission 0 of each photon by using the mass energy momentum relation. Note: A positron is an antimatter particle that has the same mass as the electron but opposite charge similarly a photon y is a massless particle of electromagnetic radiation having energy E = pc.
Transcribed Image Text:5. The free neutron is known to decay into a proton, an electron and an antineutrino (of zero rest mass) according to the following beta decay relation n → p+e¯ +v This beta decay products are measured to have a total kinetic energy of (0.781 ± 0.005) MeV. Show that this observation is consistent with the Einstein mass-energy relationship and determine the Am and the relevant energy E. (ii) An electron e- having kinetic energy 1.0 MeV has a head-on collision with a positron e* at rest. During the collision the two particles annihilate each other and are replaced by two photons of equal energy, each traveling at angles 0 with the electron's direction of motion. The reaction is e¯ +e* → 2y Determine the energy E , momentum p and angle of emission 0 of each photon by using the mass energy momentum relation. Note: A positron is an antimatter particle that has the same mass as the electron but opposite charge similarly a photon y is a massless particle of electromagnetic radiation having energy E = pc.
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