I know that for the first portion the constant force is F=176.714N. I need help finding r for the second part of question. I think the formula isL=(1/2M*R^2+m*r^2)*ω*k but im not sure. Could you please tell me if this is correct formula and what each piece of formula stands for? I am not sure about omega or the k. 3.) A 150-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50m is setin motion by wrapping a rope about the rim of the disk and pulling on the rope. What constantforce must be exerted on the rope to bring the merry-go-round from rest to an angular speed of0.500 rev/s in 2.00 s? Additionally, at t=2s, the net torque disappears and four people each witha mass of 50 kg jump onto the marry-go-round each at a distance r from the axis of rotation.When that happens, the angular speed of the merry-go-round plus people is 2.5rad/s. What is r?You can treat each person as a particle for the purpose of moment of inertia.

Using 2nd equation of motion in rotational motion: ωf=ωi+αt3.14=0+2α⇒α=1.57 rad/s2 Moment of inertia…

Answered: 3.) A 150-kg merry-go-round in the…

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I got sqrt(g/4) as my omega from part d. However, I don't how to proceed from there to answer part e,f and g