An aluminum cup of 250 cm^3 capacity is completely filled with glycerin at 25 C. How much glycerin, if any, will spill out of the cup if the temperature of both the cup and glycerin is increased to 32 C? (The coefficient of volume expansion of glycerin is 5.1 x 10^-4 /C). (Notation: cm^3 means cm- cubed, 10^-4 means 10 to the power -4). * a) 0.65 cm^3 b) 0.77 cm^3 O c) 0.82 cm^3 d) 0.34 cm^3

An aluminum cup of 250 cm^3 capacity is completely filled with glycerin at 25 C. How much glycerin, if any, will spill out of the cup if the temperature of both the cup and glycerin is increased to 32 C? (The coefficient of volume expansion of glycerin is 5.1 x 10^-4 /C). (Notation: cm^3 means cm- cubed, 10^-4 means 10 to the power -4). * a) 0.65 cm^3 b) 0.77 cm^3 O c) 0.82 cm^3 d) 0.34 cm^3

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

At "low" temperatures, the heat capacity of some materials varies with temperature as 3 12π¹ NkB T C (T) ² (£) ². 5 Here N is the number of atoms, kB is Boltzmann's constant, and Tp is the "Debye temperature," which is different for different materials. For example, 2300 K for diamond, which is particularly high. TD = How much energy would it take to raise the temperature of one mole of diamond from 100 K to 300K? O 150 Joules. 60 Joules. O 319 joules. O 630 Joules.
A baby's bath should be at a temperature of 37C. The bath already contains 10kg of water at 15'C. Approximately how much hot water, with a temperature of 50 C, should be added to achieve the desired temperature? 10kg 17 kg 12 kg 15 kg
After sitting on a shelf for a while, a can of soda at a room temperature (73∘73∘F) is placed inside a refrigerator and slowly cools. The temperature of the refrigerator is 37∘37∘F. Newton's Law of Cooling explains that the temperature of the can of soda will decrease proportionally to the difference between the temperature of the can of soda and the temperature of the refrigerator, as given by the formula below: �=��+(�0−��)�−��T=Ta+(T0−Ta)e−kt ��=Ta= the temperature surrounding the object�0=T0= the initial temperature of the object�=t= the time in minutes�=T= the temperature of the object after �t minutes�=k= decay constant The can of soda reaches the temperature of 53∘53∘F after 30 minutes. Using this information, find the value of �k, to the nearest thousandth. Use the resulting equation to determine the Fahrenheit temperature of the can of soda, to the nearest degree, after 60 minutes. Enter only the final temperature into the input box.
Please answer the question in the picture
How much heat (in joules) is required to raise the temperature of 24.4 kg of water from 19 ∘C to 88 ∘C? Express your answer using two significant figures.
A 1.5kg iron horseshoe at 800C is dropped into a bucket of water at 20 C. If the mass of water in the bucket is 5kg, what is the final temperature of the water-iron mixture, given c iron=448 J/kgoC and c water= 4187 J/kgoC?
A vertical glass tube of length L = 1.3m is half filled with a liquid at 18.7 ˚C. How much will the height of the liquid column change when the tube is heated to 31.8 ˚C? Take αglass = 1.46× 10-5/K and βliquid = 4.37× 10-5/K.
A circular 1.5 kg aluminum plate with a radius of .153 m and a thickness of 0.75 cm is in contact with a heating element. How long does it take the plate temperature to rise from 190 C to 630 C? (thermal conductivity = 200)
The escape velocity of any object from Earth is 11.2 km/s. (a) Express this speed in m/s and km/h. Speed, m/s: 11200 Speed, km/h: 40320 (b) At what temperature would oxygen molecules (molecular mass is equal to 32 g/mol) have an average velocity, v, 'ms' equal to Earth's escape velocity 11.2 km/s? Temperature: 1,89 ×108 K No, that's only partially correct
Suppose a meter stick made of steel and one made of aluminum are the same length at 0°C. What is their difference in length at 87.1°C? Express your answer in mm, to at least one digit after the decimal point.
How much ice (at 0 Celsius) must be added to 1.00kg of water at 95 Celsius so as to end up with all liquid at 15 Celsius? (Given: c(ice) = 2000 J/kgC, c(water) = 4186 J/kgC, Lf = 3.35x10^5 J/kg, and Lv = 2.26x10^6 J/kg)
Di O 11:PA (1) Suppose a person is covered head to foot by wool clothing with average thickness of 2 cm and is transferring energy of 6000 joules by conduction through the clothing for 2 minutes. What is the temperature difference across the clothing, given the surface area is 1.4m?? (Given: Thermal conductivity of wool is 0.04 W/mK) The difference in temperature = (2) A 9.15 kg sample of water at 11°C is in a calorimeter. You drop a piece of iron with a mass of 0.41 kg at 260°C into it. After the sizzling subsides, what is the final equilibrium temperature? (Given: Sp. Heat of water 1cal/g°C & Sp. Heat of iron is 0.106 cal/g°C) Equilibrium temperature in celcius =