At "low" temperatures, the heat capacity of some materials varies with temperature as 12π¹ NkB C (T) = · (£) ³. 5 Here N is the number of atoms, kB is Boltzmann's constant, and Tp is the "Debye temperature," which is different for different materials. For example, TD 2300 K for diamond, which is particularly high. How much energy would it take to raise the temperature of one mole of diamond from 100 K to 300K? O 150 Joules. O 60 Joules. O 319 joules. O 630 Joules.
At "low" temperatures, the heat capacity of some materials varies with temperature as 12π¹ NkB C (T) = · (£) ³. 5 Here N is the number of atoms, kB is Boltzmann's constant, and Tp is the "Debye temperature," which is different for different materials. For example, TD 2300 K for diamond, which is particularly high. How much energy would it take to raise the temperature of one mole of diamond from 100 K to 300K? O 150 Joules. O 60 Joules. O 319 joules. O 630 Joules.
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Transcribed Image Text:At "low" temperatures, the heat capacity of some materials varies with temperature as
3
12π¹ NkB
T
C (T)
² (£) ².
5
Here N is the number of atoms, kB is Boltzmann's constant, and Tp is the "Debye temperature," which is different for different materials. For example,
2300 K for diamond, which is particularly high.
TD
=
How much energy would it take to raise the temperature of one mole of diamond from 100 K to 300K?
O 150 Joules.
60 Joules.
O 319 joules.
O 630 Joules.
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