Some amount of heat energy is removed from a 9cm X 26cm X 46cm block of ice to cool from 0ºC to -26ºC. (Hint: to find mass, use the relation between, density, mass and volume) Calculate the following: a) The mas of ice cube in grams (density of ice = 920 kg/m3). b) The temperature difference in kelvin b) The energy removed from ice in calories . (specific heat of ice = 2093 J/kgºC)
Some amount of heat energy is removed from a 9cm X 26cm X 46cm block of ice to cool from 0ºC to -26ºC. (Hint: to find mass, use the relation between, density, mass and volume) Calculate the following: a) The mas of ice cube in grams (density of ice = 920 kg/m3). b) The temperature difference in kelvin b) The energy removed from ice in calories . (specific heat of ice = 2093 J/kgºC)
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Some amount of heat energy is removed from a 9cm X 26cm X 46cm block of ice to cool from 0ºC to -26ºC. (Hint: to find mass, use the relation between, density, mass and volume)
Calculate the following:
a) The mas of ice cube in grams
(density of ice = 920 kg/m3).
b) The temperature difference in kelvin
b) The energy removed from ice in calories
. (specific heat of ice = 2093 J/kgºC)

Transcribed Image Text:Some amount of heat energy is removed from a 9cm X 26cm X 46cm block of ice to cool from 0°C to -26°C.
(Hint: to find mass, use the relation between, density, mass and volume)
Calculate the following:
a) The mas of ice cube in grams
en
(density of ice = 920 kg/m³).
!!
b) The temperature difference in kelvin
b) The energy removed from ice in calories
(specific heat of ice = 2093 J/kg°C)
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