An air-conditioner with refrigerant-134a as the working fluid is used to keep a lab at 26°C by rejecting the waste heat to the outdoor air at 34°C. The lab gains heat through the walls and the windows at a rate of 200 kJ/min while the heat generated by the computers amounts to 850 W. Some people in the lab produce additional heat. The refrigerant enters the compressor at 500 kPa as a saturated vapor at a rate of 100 L/min and leaves at 1200 kPa and 55°C. QH = 6.72 kW. 1) Determine the rate of heat generated by the people in the room. 2) Calculate the COP of the air-conditioner.
An air-conditioner with refrigerant-134a as the working fluid is used to keep a lab at 26°C by rejecting the waste heat to the outdoor air at 34°C. The lab gains heat through the walls and the windows at a rate of 200 kJ/min while the heat generated by the computers amounts to 850 W. Some people in the lab produce additional heat. The refrigerant enters the compressor at 500 kPa as a saturated vapor at a rate of 100 L/min and leaves at 1200 kPa and 55°C. QH = 6.72 kW. 1) Determine the rate of heat generated by the people in the room. 2) Calculate the COP of the air-conditioner.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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An air-conditioner with refrigerant-134a as the working fluid is used to keep a lab at 26°C by rejecting the waste heat to the outdoor air at 34°C. The lab gains heat through the walls and the windows at a rate of 200 kJ/min while the heat generated by the computers amounts to 850 W. Some people in the lab produce additional heat. The refrigerant enters the compressor at 500 kPa as a saturated vapor at a rate of 100 L/min and leaves at 1200 kPa and 55°C. QH = 6.72 kW.
1) Determine the rate of heat generated by the people in the room.
2) Calculate the COP of the air-conditioner.
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