V3.An aerated BOD bottle is filled with substrate and microbial cells. You have determined the following parameters for this mixture: - Substrate yield,Y=0.60mg/Lbiomass/mg/Lsubstrate - Specific growth rate,μ=2.0day−1 - Rate of substrate utilization=15,000mg/L−hr- Substrate concentration=275mg/L- Half-saturation constant=25mg/LDetermine: a. The microbial growth rate/biomass utilization rate.9000mg/L−hrb. The maximum specific growth rate.2.18/ day c. The biomass concentration.4500mg/L An aerated BOD bottle is filled with substrate and microbial cells. You have determined thefollowing parameters for this mixture:oSubstrate yield, Y = 0.60 mg/L biomass / mg/L substrateSpecific growth rate, μ = 2.0 day¹oRate of substrate utilization = 15,000 mg/L-hro Substrate concentration = 275 mg/Lo Half-saturation constant = 25 mg/LDetermine:a. The microbial growth rate/biomass utilization rate. 9000 mg/L-hrb. The maximum specific growth rate. 2.18/dayc. The biomass concentration. 4500 mg/L

Given, Y = 0.60 μ = 2/day Ks = 25 mg/L dSdt = 15000 mg/L-hr S = 275 mg/L

Answered: An aerated BOD bottle is filled with…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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V3. An aerated BOD bottle is filled with substrate and microbial cells. You have determined the following parameters for this mixture: - Substrate yield, Y=0.60mg/L biomass /mg/L substrate - Specific growth rate, μ=2.0 day −1 - Rate of substrate utilization =15,000mg/L−hr - Substrate concentration =275mg/L - Half-saturation constant =25mg/L Determine: a. The microbial growth rate/biomass utilization rate. 9000mg/L−hr b. The maximum specific growth rate. 2.18 / day c. The biomass concentration. 4500mg/L

An aerated BOD bottle is filled with substrate and microbial cells. You have determined the
following parameters for this mixture:
o
Substrate yield, Y = 0.60 mg/L biomass / mg/L substrate
Specific growth rate, μ = 2.0 day¹
o
Rate of substrate utilization = 15,000 mg/L-hr
o Substrate concentration = 275 mg/L
o Half-saturation constant = 25 mg/L
Determine:
a. The microbial growth rate/biomass utilization rate. 9000 mg/L-hr
b. The maximum specific growth rate. 2.18/day
c. The biomass concentration. 4500 mg/L

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