Microbial growth in an activated sludge system can be described by the Monod model. If the maximum specific growth rate constant µmax is 1.2 day-1 and the half saturation coefficient Ks is determined to be 30 mg/L as COD, what should be the organic substrate concentration if you want to achieve a specific growth rate (µ) of 0.6 day-1? ( )

Q: After an isocratic elution has been optimized with several solvents, the chromatogram has a…

A: There are basically two solvent delivery system in the gas chromatography technique First is…

Q: MEK, Methyl ethyl ketone (CH3C(O)CH2CH3) has waste code D035. Why does MEK have high solubility in…

A: Methyl Ethyl Ketone  is a colorless, liquid chemical substance that is used in many industrial…

Q: The initial ultimate BOD after mixing of the James River is 32.5 mg/L. The DO in the river after the…

A: The critical point(t) is determined by the equation: tc=1Kd(1-D0L) Where Kd is the deoxygenation…

Q: 1 The lower the water turbidity, the higher the allowable scour velocity in sedimentation tank.( ) 2…

A: 1 True - Lower water turbidity allows for higher allowable scour velocity as the particles in the…

Q: For a sample of water with the ionic composition shown below, the Carbonate and Non-carbonate…

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Q: Some wastewater has a BOD, of 180 mg/L at 20°C. The reaction rate K at that temperature has heen…

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Q: Increasing wasting from the secondary treatment process: Decreases SRT and MLSS concentration.…

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Q: (10 6-13. Determine the lime and soda ash dose, in mg/L as CaCO3, to soften the 4-5 following water…

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Q: 2. A CSTR (10 L) with Gordonia bacterial cells is being used to treat hazardous waste containing the…

A: Volume of CSTR, V = 10 LIntake concentration of RDX, Co = 0.22 mg/LFlowrate (Q) = 2.5 L/dayDecay…

Q: The theoretical yield coefficient can be estimated from the observed yield coefficient if the…

A: Cell mass and item arrangement by microorganisms can be portrayed quantitatively by yield…

Q: An activated sludge system using CSTR with sludge recycle has an influent flow rate (Q°) of 2.5 MGD…

A: We have to determine the value of hydraulic retention time he solids retention time and activated…

Q: A bio-tower composed of a modular plastic medium of 6 m is used as secondary treatment component in…

A: A bio-tower composed of a modular plastic medium of 6 m is used as a secondary treatment component…

Q: For an industrial activated sludge treatment process, the biomass concentration (X) is 2,200 mg…

A: The formula to calculate the microbial growth is given by, rg=k×S×Y×XKs+S Here, k is Max substrate…

Q: The secondary NAAQS for SO2 is 0.5 ppm (for a 3-hour averaging time). Calculate the equivalent…

A: Given:- The secondary NAAQS for SO2 is 0.5 ppm To find:- The equivalent concentration in pg/m3

Biological Processes

Biological solid waste includes bacterial and contaminated waste produced by living individuals. Its treatment is essential to prevent the spread of any air-borne or water-borne diseases or diseases transmitted from one organism to another in a food chain. There are many benefits of the biological solid waste treatment and some of them are: the minimized quantity of waste substance, waste control, eradicating any disease-causing pathogens, generation of biogas, composting, anaerobic digestion, bio drying, mechanical biological treatment, microbial fuel cell, phytoremediation, and biofiltration. The final products of the biological solid waste treatment may be recycled to obtain organic fertilizers or disposed of in SWDS (Solid Waste Disposal Site) after proper treatment.