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- An AC Motor with impedance Z₁ = 45+j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf), b) Average power (active power), c) Reactive power, d) Complex power, e) Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 31.481 uF O b. a) pf=0.357, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O e. a) pf=0.460, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 31.481 uF O f. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054+j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value 15.741 uF

- An AC Motor with impedance Z₁ = 45+j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf), b) Average power (active power), c) Reactive power, d) Complex power, e) Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 31.481 uF O b. a) pf=0.357, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O e. a) pf=0.460, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 31.481 uF O f. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054+j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value 15.741 uF

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Circuit theory Power Analysis I want the solution within 10 minutes
- An AC Motor with impedance Z₁ = 45+j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf), b) Average power (active power), c) Reactive power, d) Complex power, e) Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 31.481 uF O b. a) pf=0.357, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O e. a) pf=0.460, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 31.481 uF O f. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054+j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value 15.741 uF
Transcribed Image Text:- An AC Motor with impedance Z₁ = 45+j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf), b) Average power (active power), c) Reactive power, d) Complex power, e) Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 31.481 uF O b. a) pf=0.357, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value 15.741 uF O e. a) pf=0.460, b) active power = 46.108 W, c) reactive power = 102.462 VAR, d) Complex Power= 46.108 + j102.462 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 31.481 uF O f. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054+j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 + j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W, c) reactive power = 102.462 VAR, d) Complex Power= 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value 15.741 uF
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