An AC generator consists of eight turns of wire, each having area A = 0.0860 m2, with a total resistance of 10.8 Ω. The loop rotates in a magnetic field of 0.559 T at a constant frequency of 61.5 Hz. (a) Find the maximum induced emf. (b) What is the maximum induced current? (c) Determine the induced emf and current as functions of time. (d) What maximum torque must be applied to keep the coil turning?

Q: An AC generator is to have a maximum output of 300 V. Each coil has an area of 0.105 m2 and a…

A: Vmax=NBAω     N=VmaxBA2πf  =300 V0.746 T0.105 m22π43.0 Hz=14

Q: (A) 2.25 (B) 5. The armature of a simple AC generator consists of a square loop of wire with one…

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Q: Problem 4: Suppose a 55 cm long, 12 cm diameter solenoid has 1000 loops. Part (a) Calculate the…

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Q: 8. (a) A 40.4 mH inductor is connected as in the figure to an ac generator with Em = 30.0 V. What is…

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Q: Problem 3. An RL circuit in which the inductance is 4.00 H and the resistance is 5.00 ohms is…

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Q: A 15 mH inductor is connected to an AC generator with a frequency of 60 Hz and carries a current i…

A: The given problem is based upon the emf across an inductor when a certain amount of current flows…

Q: 1) A voltage is varied in a primary solenoid with 2900 +/- 100 turns of coil. The length of the…

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Q: Use the worked example above to help you solve this problem. An AC generator consists of eight turns…

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Q: The rotating loop in an AC generator is a square 11.0 cm on a side. It is rotated at 75.0 Hz in a…

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Q: Problem 8: Suppose a large power plant generates electricity at 12.0 kV. Its old transformer once…

A: Part (a)Find the relation between current, power and voltage.

Q: A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage…

A: Given Data:Voltage used to generate electricity Voltage gain by the old transformer Voltage gain by…

Q: How much of a change in current over time would produce a self-induced EMF of 6.00V in a  10µH…

A: self induced emf produced, ε=6.00 V Inductance in an inductor, L=10 μH=10×10-6 H=10-5H self…

Q: An AC generator is to have a maximum output of 340 V. Each coil has an area of 0.121 m² and a…

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Q: |Problem 1: An inductor with L= 4.5 H is in a closed circuit with I = 0.35 A (see the diagram). When…

A: Given:The inductance: L = 4.5 H;The current flowing in the circuit initially: Ii = 0.35 A;The…

Q: An AC generator is to have a maximum output of 308 V. Each coil has an area of 0.108 m2 and a…

A: Given, Emf of the AC generator, ε= 308 V area, A = 0.108 m2 resistance, R = 15.4 Ω the magnetic…

Q: A secondary coil is located inside a primary coil. The coils contain no ferromagnetic core. A) The…

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Q: An AC generator with ten turns of wire, each having area A = 0.08 m?, and having a total resistance…

A: Given, Number of turns N = 10 turns             Area A = 0.08 m2            Resistance R = 12.0 Ω…

Q: An ac electrical generator is made by turning a flat coil in a uniform constant magnetic field of…

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Q: The rotating loop in an AC generator is a square 11.0 cm on a side. It is rotated at 75.0 Hz in a…

A: Given, The side of the rotating loop is square, A = 11 cm = 0.11 m frequency of the rotation, f =…

Q: A solenoid with 495 turns has a length of 7.50 cm and a cross-sectional area of 3.10 x 10-9 m2. Find…

A: Induction is the phenomenon of inducing an emf in a coil by changing the magnetic flux around it. A…

Q: The current in an inductor decreases linearly from 2 mA to zero in 4 ms. Calculate the average emf…

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Q: An AC generator is to have a maximum output of 340 V. Each coil has an area of 0.132 m2 and a…

A: SOlution: given that E = 340 V A = 0.132 m2 R = 16.5 ohm B = 0.766 T f = 39.9 Hz

Q: A 54.0 mH inductor is connected as in the figure to an ac generator with εm = 35.0 V. What is the…

A: (a) The expression to solve for the amplitude of the current is as follows: I=εmXLI=εm2πfL…

Q: Use the worked example above to help you solve this problem. An AC generator consists of eight turns…

A: Since you have asked multiple questions we will solve the first question for you. If you want any…

Q: Measurements on a solenoid coil (inductor) at a particular instant in time indicate that the current…

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Q: An inductor of L = 6.95 H with negligible resistance is placed in series with a 8 = 15.7 V battery,…

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Q: ) What is the inductance of a coil if it produces an emf of 8.5V when the current in it changes…

A: Given: The induced emf is 8.5 V. The initial current is -20 mA. The final current is 24 mA. The time…

Q: In the given circuit an inductor of L = 6.20-mH and a resistor of R = 12.4-2 resistor are connected…

A: Since,  Voltage across inductor  VL = Ee-Rt/L  So voltage across resistance  VR = E - Ee-Rt/L

Voltage Across Inductor

An actor is a passive electrical component that consists of a coil bent in the form of wire which uses electromagnetism to produce electric current through the coil. When the electric current flows through a conductor that is the coil, a magnetic flux is developed around the conductor. This flow of current through the coil creates a magnetic field based on Fleming's Right-hand thumb rule. If there is any decrease in the current passing through the inductor, then the magnetic field will also decrease and energy is released through the generation of electric current. There is also a secondary voltage inducing in the same coil due to the magnetic flux, since it opposes any changes in the electric current flowing through the circuit. An inductor is also called choke, coil, or solenoid. A choke is designed to block certain frequencies when the DC current passes. A winding coil is coated with insulation to give extra insulation and protect the circuit. They are usually tightly wrapped around a central core which is cylindrical in nature so that the magnetic flux can be induced. The solenoid is a three-dimension coil that is used to exhibit electromagnetism when the magnetic field is developed due to the current flowing through the coil. The sign convention of the inductor is the same as the power dissipating device. When the current flows into the positive side of the voltage across the inductor, the value is positive and the inductor dissipates power whereas when the inductor releases the power back to the circuit, the current has a negative sign convention.