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|Problem 1: An inductor with L= 4.5 H is in a closed circuit with I = 0.35 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.11 s. Randomized Variables L=4.5 H I=0.35 A At = 0.11 s L იიიიიიიიი

|Problem 1: An inductor with L= 4.5 H is in a closed circuit with I = 0.35 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.11 s. Randomized Variables L=4.5 H I=0.35 A At = 0.11 s L იიიიიიიიი

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Problem 1:

Part (a)  Express the magnitude of the average induced emf on the inductor, εave, in terms of L, I, and Δt.

εave = ______

Part (b)  Calculate the numerical value of εave in volts.  

εave = ______

 

 

Problem 1: An inductor with L = 4.5 H is in a closed circuit with I = 0.35 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.11 s. Randomized Variables L = 4.5 H I=0.35 A At = 0.11 s L 000000000
Transcribed Image Text:Problem 1: An inductor with L = 4.5 H is in a closed circuit with I = 0.35 A (see the diagram). When the switch is opened, the current goes to zero in At = 0.11 s. Randomized Variables L = 4.5 H I=0.35 A At = 0.11 s L 000000000
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