A series RLC circuit is driven in such a way that the maximum voltage across the inductor is 1.50 times the maximum voltage across the capacitor and 2.10 times the maximum voltage across the resistor. (a) WWhat is o for the circuit? The resistance is 51.8 Q and the current amplitude is 150 mA. (b) What is the amplitude of the driving emf?
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- A single-loop circuit consists of a 7.2 Q resistor, 11.9 H inductor, and a 3.3 µF capacitor. Initially the capacitor has a charge of 6.1 UC and the current is zero. Calculate the charge on the capacitor N complete cycles later for (a) N = 5, (b) N =10, and (c)N = 100. (a) Number i Units (b) Number i Units (c) Number UnitsInitially, an inductor with no resistance carries a constant current. Then the current is brought to a new constant value twice as large. After this change, when the current is constant at its higher value, what has happened to the emf in the inductor?A 3.5 mH inductor and a 4.5 mH inductor are connected in series and a time varying current is established in them. When the total emf of the combination is 16 V, what is the emf of the larger inductor?
- A loop of wire has a self-inductance of 5.5 mH. You pass a current of 9.0 Amps though the loop, and then drop the current to 0 at a contastant rate over 3.5 seconds. What is the EMF generated?A 10 -mH inductor and a 25 MF (micro F) capacitor are connected in parallel. The combination is in series with a resistor and a 15 Ohm resistor and 10V, 160Hz emf. (a) What is the current through the resistor? (b) What is the phase angle?A 14.0 mH inductor makes the current drop from 178 mA to 66.0 mA in only 10.0 μs. What is the potential difference across the inductor? 0.00157 V -92.4 V -249 V 157 V
- In a home stereo system, low sound frequencies are handled by large “woofer” speakers, and high frequencies by smaller “tweeter” speakers. For the best sound reproduction, low-frequency currents from the amplifier should not reach the tweeter. One way to do this is to place a capacitor in series with the 8.0 Ω resistance of the tweeter; one then has an RLC circuit with no inductor L (that is, an RLC circuit with L = 0). What value of C should be chosen so that the current through the tweeter at 200 Hz is half its value at very high frequencies?In the circuit in the figure Ry R emf of the battery&= 25 V. Wn All the inductors are of the R same inductance, L=0.064 H and of negligible resistances. Resistances of the resistors %3D are Ro = 62, Ry = 1, R2 = 81, Rg = 8N, R, = 152, Rg = 992, %3D %3D %3D Re = 82. The switch S is closed at the time t=D0. %3D Find the current flowing in Ro immediately after the switch S is closed. RU(a) What is the characteristic time constant of a 25.2 mH inductor that has a resistance of 4.02 N? ms (b) If it is connected to a 12.0 V battery, what is the current after 12.5 ms? A
- In a home stereo system, low sound frequencies are handled by large "woofer" speakers, and high frequencies by smaller "tweeter" speakers. For the best sound reproduction, low-frequency currents from the amplifier should not reach the tweeter. One way to do this is to place a capacitor in series with the 9.0 Ω resistance of the tweeter; one then has an RLC circuit with no inductor L (that is, an RLC circuit with L = 0). What value of C should be chosen so that the current through the tweeter at 200 Hz is half its value at very high frequencies?A series RL circuit with R = 19 0, and L = 6 H has a constant voltage E = 150 V applied att = 0 by the closing of a switch. R E t =0 Find the time at which VR = VL. elle