A 54.0 mH inductor is connected as in the figure to an ac generator with εm = 35.0 V. What is the amplitude of the resulting alternating current if the frequency of the emf is (a)0.760 kHz and (b)6.08 kHz? The image displays an electrical circuit diagram featuring an inductor. The diagram includes the following components:1. **AC Voltage Source (\( \mathcal{E} \))**: Represented by a circle with a sine wave inside, indicating an alternating current (AC) source. It has a label \( \mathcal{E} \) with an upward red arrow next to it.2. **Inductor (L)**: Shown as a coil, this component is labeled with the letter \( L \).3. **Current (\( i_L \))**: An arrow pointing downward next to the inductor, labeled \( i_L \), indicates the direction of the current through the inductor.4. **Voltage (\( v_L \))**: Another arrow pointing downward next to the current arrow, labeled \( v_L \), represents the voltage across the inductor.The diagram approximately symbolizes a basic series circuit with an AC voltage source connected in series with an inductor. The circuit is used to analyze the behaviors of current and voltage across the inductor in response to an AC supply.

(a) The expression to solve for the amplitude of the current is as follows: I=εmXLI=εm2πfL…

Answered: A 54.0 mH inductor is connected as in…

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