Problem 2 For the same system in Problem 1, the process is run until 50 mol% of the benzene originally in the still-pot has been vaporised. Determine a) the amount of o-xylene remaining in the still pot b) the amount and composition of the distillate c) which of the runs takes longer

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Problem 1
A simple (i.e. single equilibrium stage) batch still is being used to separate benzene
from o-xylene; a system which may be assumed to have a constant relative volatility
of 6.7. The feed to the still is 1000 mol of 60 mol% benzene. The process is run until
the instantaneous distillate composition is 70 mol% benzene. Determine:
a) the composition and amount of the residue remaining in the still pot
b) the amount and average composition of the distillate
c) the time required for the process to run if the boil-up rate is 50 mol/h
Problem 2
For the same system in Problem 1, the process is run until 50 mol% of the benzene
originally in the still-pot has been vaporised. Determine
a) the amount of o-xylene remaining in the still pot
b) the amount and composition of the distillate
c) which of the runs takes longer

 

plz solve question 2 and explain every step

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Follow-up Question

Amount of benzene in Still pot:

ABW=W·xwABW=200 mol

 

Can you explain why did you write 200 mol instead of 300 mol because 50% of the benzene has evaporated so the remaining should be 300 mol not 200 mol 

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Follow-up Question

Amount of benzene in Still pot:

ABW=W·xwABW=200 mol 

how did this become 200 when 300 mol of benzene has evaporated 

600 -300 = 200 ?

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Follow-up Question

Amount of benzene in Still pot:

ABW=W·xwABW=200 mol

should not this be 300 mol as 50% has evaporated? (300+300 =600)?

 

 

AOFAOWα=ABFABW400AOW6.7=600200AOW=339.506 mol

and what does this step mean? what is AOFAOW and ABFABW400AOW6.7

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Follow-up Question

Amount of benzene in Still pot:

ABW=W·xwABW=200 mol

Amount of o-xylene in feed:

AOF=F×1-xFAOF=1000×0.4AOF=400 mol

Can you explain these two steps plz

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