Ammonia gas can be prepared by the reaction of a metal oxide such as calcium oxide with ammonium chloride. CaO(s) + 2NH4Cl(s) → 2 NH3 (g) + H₂O(g) + CaCl₂ (s) If 111 g of CaO and 265 g of NH4Cl are mixed, what is the limiting reactant, and what mass of NH3 can be produced? The limiting reactant is Mass of NH3 = g
Ammonia gas can be prepared by the reaction of a metal oxide such as calcium oxide with ammonium chloride. CaO(s) + 2NH4Cl(s) → 2 NH3 (g) + H₂O(g) + CaCl₂ (s) If 111 g of CaO and 265 g of NH4Cl are mixed, what is the limiting reactant, and what mass of NH3 can be produced? The limiting reactant is Mass of NH3 = g
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![**Preparation of Ammonia Gas via Reaction of Calcium Oxide with Ammonium Chloride**
Ammonia gas can be prepared by the reaction of a metal oxide such as calcium oxide with ammonium chloride.
The chemical equation for the reaction is:
\[ \text{CaO(s) + 2 NH}_4\text{Cl(s) } \rightarrow 2 \text{ NH}_3\text{(g) + H}_2\text{O(g) + CaCl}_2\text{(s)} \]
If 111 g of CaO and 265 g of NH\(_4\)Cl are mixed, what is the limiting reactant, and what mass of NH\(_3\) can be produced?
**The limiting reactant is:**
\[ \underline{\hspace{2cm}} \]
**Mass of NH\(_3\):**
\[ \text{NH}_3 = \underline{\hspace{2cm}} \text{ g} \]
**Drag and drop your selection from the following list to complete the answer:**
- NH\(_4\)Cl
- NH\(_3\)
- CaCl\(_2\)
- CaO
This educational exercise involves stoichiometric calculations to determine the limiting reactant and the amount of product formed in a chemical reaction, which are foundational concepts in chemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F883e3e80-624e-4e0d-88a1-3570ac65b326%2F1db704fd-79fe-49d8-aef0-1c43ea64ebd3%2Frxfdpi9_processed.png&w=3840&q=75)
Transcribed Image Text:**Preparation of Ammonia Gas via Reaction of Calcium Oxide with Ammonium Chloride**
Ammonia gas can be prepared by the reaction of a metal oxide such as calcium oxide with ammonium chloride.
The chemical equation for the reaction is:
\[ \text{CaO(s) + 2 NH}_4\text{Cl(s) } \rightarrow 2 \text{ NH}_3\text{(g) + H}_2\text{O(g) + CaCl}_2\text{(s)} \]
If 111 g of CaO and 265 g of NH\(_4\)Cl are mixed, what is the limiting reactant, and what mass of NH\(_3\) can be produced?
**The limiting reactant is:**
\[ \underline{\hspace{2cm}} \]
**Mass of NH\(_3\):**
\[ \text{NH}_3 = \underline{\hspace{2cm}} \text{ g} \]
**Drag and drop your selection from the following list to complete the answer:**
- NH\(_4\)Cl
- NH\(_3\)
- CaCl\(_2\)
- CaO
This educational exercise involves stoichiometric calculations to determine the limiting reactant and the amount of product formed in a chemical reaction, which are foundational concepts in chemistry.
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