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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3C12 (g)→2AICI3 (s) You are given 34.0 g of aluminum and 39.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 34.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA ? Value Units Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 39.0 g of chlorine gas, Cl2 ? Express your answer to three significant figures and include the appropriate units.

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3C12 (g)→2AICI3 (s) You are given 34.0 g of aluminum and 39.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 34.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA ? Value Units Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 39.0 g of chlorine gas, Cl2 ? Express your answer to three significant figures and include the appropriate units.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2 (g)–→2AICI3 (s) In the following chemical reaction, 2 mol of A will react with 1 mol of B to produce 1 mol of A2 B without anything left over: You are given 34.0 g of aluminum and 39.0 g of chlorine gas. 2A + B -A,В But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 34.0 g of aluminum? 1 mol A2B 2.8 metA x = 1.4 mol A,B 2 mełA Express your answer to three significant figures and include the appropriate units. 1 mol A2B 3.2 motB x 3.2 mol A2B • View Available Hint(s) 1 metB Notice that less product is formed with the given amount of reactant A. Thus, A is the limiting reactant, and a maximum of 1.4 mol of A2B can be formed from the given amounts. HA Value Units Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 39.0 g of chlorine gas, Cl2 ? Express your answer to three significant figures and include the appropriate units.
Transcribed Image Text:Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s) + 3Cl2 (g)–→2AICI3 (s) In the following chemical reaction, 2 mol of A will react with 1 mol of B to produce 1 mol of A2 B without anything left over: You are given 34.0 g of aluminum and 39.0 g of chlorine gas. 2A + B -A,В But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 34.0 g of aluminum? 1 mol A2B 2.8 metA x = 1.4 mol A,B 2 mełA Express your answer to three significant figures and include the appropriate units. 1 mol A2B 3.2 motB x 3.2 mol A2B • View Available Hint(s) 1 metB Notice that less product is formed with the given amount of reactant A. Thus, A is the limiting reactant, and a maximum of 1.4 mol of A2B can be formed from the given amounts. HA Value Units Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 39.0 g of chlorine gas, Cl2 ? Express your answer to three significant figures and include the appropriate units.
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