Although KOH, RBOH, and CsOH have little association between metal and hydroxide in aqueous solution, Li* and Na* do form complexes with OH": [LIOH(19)| K, = (Li*]|OH"] Li + OH LIOH(aq) =0.83 Na" + OH NaOH(a9) (NaOH(aq)| |Na* ]|OH" | -0.20 Prepare a table showing initial and final concentrations of Li", OH", and LIOH(aq) in 1.00 F LIOH solution. Caculate the fraction of lithium in the form LIOH(aq) at equilibrium. fraction as LIOH(aq):
Although KOH, RBOH, and CsOH have little association between metal and hydroxide in aqueous solution, Li* and Na* do form complexes with OH": [LIOH(19)| K, = (Li*]|OH"] Li + OH LIOH(aq) =0.83 Na" + OH NaOH(a9) (NaOH(aq)| |Na* ]|OH" | -0.20 Prepare a table showing initial and final concentrations of Li", OH", and LIOH(aq) in 1.00 F LIOH solution. Caculate the fraction of lithium in the form LIOH(aq) at equilibrium. fraction as LIOH(aq):
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Although KOH, RBOH, and CSOH have little association between metal and hydroxide in aqueous solution, Li" and Na*
do form complexes with OH":
[LIOH(19)]
K =
[Li* ||OH"|
Lit + OH LIOH(aq)
=0.83
Na* + OH = NaOH(aq)
[NAOH(aq)]
K =
= 0.20
|Na ||OH"|
Prepare a table showing initial and final concentrations of Li*, OH", and LIOH(aq) in 1.00 F LIOH solution. Calculate the
fraction of lithium in the form LIOH(aq) at equilibrium.
fraction as LIOH(aq):
Publisher W freeman
Question Source Quantitative Chemical Analysis 10e](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe91018f9-acab-4dac-9df7-c60c92691707%2Ff91e7a97-800a-4b4e-b2a5-d160d01b9df7%2Fq5dv8pj_processed.png&w=3840&q=75)
Transcribed Image Text:Although KOH, RBOH, and CSOH have little association between metal and hydroxide in aqueous solution, Li" and Na*
do form complexes with OH":
[LIOH(19)]
K =
[Li* ||OH"|
Lit + OH LIOH(aq)
=0.83
Na* + OH = NaOH(aq)
[NAOH(aq)]
K =
= 0.20
|Na ||OH"|
Prepare a table showing initial and final concentrations of Li*, OH", and LIOH(aq) in 1.00 F LIOH solution. Calculate the
fraction of lithium in the form LIOH(aq) at equilibrium.
fraction as LIOH(aq):
Publisher W freeman
Question Source Quantitative Chemical Analysis 10e
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