Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 16 Allen's hummingbirds has been under study in Arizona. The average weight for these birds isx = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o = 0.24 gram.When finding an 80% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.)(a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.)lower limitupper limitmargin of error (c) Interpret your results in the context of this problem.O we are 80% confident that the true average weight of Allen's hummingbirds falls within this interval.O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20.O We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval.O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.80.(d) Which equation is used to find the sample size n for estimating u when o is known?On =O-(On =2,0On = VEOn =Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.13 for the mean weights of the hummingbirds. (Round up to the nearest whole number.)hummingbirds

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Answered: Allen's hummingbird (Selasphorus sasin)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with σ = 0.24 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) σ is known σ is unknown n is large uniform distribution of weights normal distribution of weights (c) Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.15 for the mean weights of the hummingbirds. (Round up to the nearest whole number.)hummingbirds
It is known that the serum cholesterol level of females is normally distributed and its population variance is 45 mg/100 mL. Researchers decided to estimate the population mean serum cholesterol level. They observed a sample average serum cholesterol level of 220 mg/ml in 35 females. a. Compute a 95% confidence interval for the population mean serum cholesterol level of females. b. Researchers at another university are going to collect new data and they are assuming that the female serum cholesterol level is Normally distributed with a population variance of 45. How many subjects do they have to observe to have a 95% confidence interval with a final length of at most 3?
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 11 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with σ = 0.28 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit-? upper limit-? margin of error-? (b) Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.06 for the mean weights of the hummingbirds. (Round up to the nearest whole number.) _________hummingbirds
Given two independent random samples with the following results: n1=12x‾1=73s1=27n1=12x‾1=73s1=27 n2=12x‾2=102s2=22n2=12x‾2=102s2=22 Use this data to find the 95%95% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval.
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with σ = 0.22 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) uniform distribution of weightsσ is knownσ is unknownn is largenormal distribution of weights (c) Interpret your results in the context of this problem. We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval. We are 80% confident that the true average weight of Allen's…
Is the birth rate of the infants in this sample significantly different from that of the general population at alpha level of 0.05? Explain your response.
A sample of 164 was selected from a large population. 66% of the sample had a characteristic of interest. Calculate a 90% confidence interval estimate for the proportion of the population with the characteristic.
One method for measuring air pollution is to measure the concentration of carbon monoxide, or CO, in the air. Suppose Nina, an environmental scientist, wishes to estimate the CO concentration in Zagreb, Croatia. She randomly selects 45 locations throughout the city measures the CO concentration at each location. Based on her 45 samples, she computes the margin of error for a 95% t-confidence interval for the mean concentration of CO in Zagreb, in µg/m³, to be 4.28. What would happen to the margin of error if Nina decreases the confidence level to 90%? Nina increases the confidence level to 99%? Nina decreases the sample size to 33 locations? Nina increases the sample size to 65 locations? Answer Bank Increase Stay the same Decrease
A confidence interval is desired for the true mean stray-load loss (Watts) for a certain type of induction motor. Assume that the stray-load loss is normally distributed with =3.3Watts. Situation 3: You take 100 measurements of stray-load loss from induction motors and determine that the mean of your sample is 53.6 Watts. When you calculate the 95% confidence interval for this situation, you get: (52.95 Watts, 54.25 Watts) is a 95% confidence interval for M. Compare this confidence interval to the interval you calculated in Situation 1. They are both 95% confidence intervals, but they have different sample sizes. What effect did sample size have on the interval estimate endpoints? Question 1: 25 sample size, Confidence Interval: (52.3064,54.8936)
A greenhouse is growing a large number of poinsettia plants. An employee is monitoring their growth and selects 100 of them at random to measure. The plants have an average height of 5.5 inches, with an SD of 2 inches. Calculate a 90%-confidence interval for the average height of all the poinsettia plants growing in the greenhouse.
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 12 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with a = 0.22 gram. When finding an 80% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) Oo is known Oo is unknown O uniform distribution of weights O normal distribution of weights On is large (c) Interpret your results in the context of this problem. We are 80% confident that the true average weight of…
Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82412 lb, s=0.00573 lb. Use a confidence level of 95% to complete parts (a) through (d) below. Part 1 a. Identify the critical value tα/2 used for finding the margin of error. tα/2 = Part 2 b. Find the margin of error. Part 3 c. Find the confidence interval estimate of Part 4 d. Write a brief statement that interprets the confidence interval.

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